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dolphi86 [110]
3 years ago
10

How do i do this question y=-1/2x-2 i am suppoted to graph it

Mathematics
1 answer:
inysia [295]3 years ago
8 0
No your supposed to do the math and cancel out each nunber until you find y
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Write two verbal expressions for n-5
sukhopar [10]

A number less than five

OR

n minus five

7 0
3 years ago
Which sequence of transformations carries ABCD onto HGFE?
Korvikt [17]
D.

Look at top left coordinate (2,-1)
Eight units left = (2-8,-1) = (-6,-1)
Reflection across x axis means change in y
(-6,-1) to (-6, 1) :)
6 0
2 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
A distance of 30 miles on a map is represented by a 2-inch line. If the map is enlarged to 3 times its size, what will be the sc
vichka [17]

Answer:

\frac{1}{5}\frac{in}{miles}

Step-by-step explanation:

we know that

The original scale of the map is

\frac{2}{30}\frac{in}{miles}=\frac{1}{15}\frac{in}{miles}

If the map is enlarged to 3 times its size

then

the new scale will be

\frac{2*3}{30}\frac{in}{miles}=\frac{6}{30}=\frac{1}{5}\frac{in}{miles}

4 0
2 years ago
Help me plz and explain how u got it
mario62 [17]
The baskets that DO have eggs in the baskets are  2 3 4 26 34 46 
i am not 100% sure if its right but i think it is 
hope i helped
5 0
3 years ago
Read 2 more answers
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