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satela [25.4K]
3 years ago
13

Please help me I have been stuck on this question for ages

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is P(g)=\frac{4}{9}

and P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}

Thus \frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}

\frac{g}{g+r}=\frac{4}{9}

\Rightarrow 9g=4g+4r

\Rightarrow 5g=4r\quad \ldots(i)

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}

\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}

\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}

\Rightarrow 10g+10r+60=23g+46

\Rightarrow 10r+14=13g\ quad \ldots(ii)

Substitute the value of g in equation (ii)[/tex]

\Rightarrow 10\times \frac{5}{4}g+14=13g

\Rightarrow \frac{25}{2}g+14=13g

\Rightarrow g=28

Therefore r=35

Thus there 28 green counter and 35 red counter

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