Answer:
Initial concentration of HI is 5 mol/L.
The concentration of HI after
is 0.00345 mol/L.
Explanation:
![2HI(g)\rightarrow H_2(g)+I_2(g) ](https://tex.z-dn.net/?f=2HI%28g%29%5Crightarrow%20H_2%28g%29%2BI_2%28g%29%0A)
Rate Law: ![k[HI]^2 ](https://tex.z-dn.net/?f=k%5BHI%5D%5E2%0A)
Rate constant of the reaction = k = ![6.4\times 10^{-9} L/mol s](https://tex.z-dn.net/?f=6.4%5Ctimes%2010%5E%7B-9%7D%20L%2Fmol%20s)
Order of the reaction = 2
Initial rate of reaction = ![R=1.6\times 10^{-7} Mol/L s](https://tex.z-dn.net/?f=R%3D1.6%5Ctimes%2010%5E%7B-7%7D%20Mol%2FL%20s)
Initial concentration of HI =![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
![1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-7%7D%20mol%2FL%20s%3D%286.4%5Ctimes%2010%5E%7B-9%7D%20L%2Fmol%20s%29%5BHI%5D%5E2)
![[A_o]=5 mol/L](https://tex.z-dn.net/?f=%5BA_o%5D%3D5%20mol%2FL)
Final concentration of HI after t = [A]
t = ![4.53\times 10^{10} s](https://tex.z-dn.net/?f=4.53%5Ctimes%2010%5E%7B10%7D%20s)
Integrated rate law for second order kinetics is given by:
![\frac{1}{[A]}=kt+\frac{1}{[A_o]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%3Dkt%2B%5Cfrac%7B1%7D%7B%5BA_o%5D%7D)
![\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%3D6.4%5Ctimes%2010%5E%7B-9%7D%20L%2Fmol%20s%5Ctimes%204.53%5Ctimes%2010%5E%7B10%7D%20s%2B%5Cfrac%7B1%7D%7B%5B5%20mol%2FL%5D%7D)
![[A]=0.00345 mol/L](https://tex.z-dn.net/?f=%5BA%5D%3D0.00345%20mol%2FL)
The concentration of HI after
is 0.00345 mol/L.
Explanation:
In order to find whether it will sink or float in water we must first find the density of the object
The density of a substance can be found by using the formula
![density = \frac{mass}{volume} \\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C)
From the question
mass = 18 g
volume = 9 cm³
So we have
![density = \frac{18}{9} \\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7B18%7D%7B9%7D%20%20%5C%5C%20)
We have the density as 2.0 g/cm³
The object will sink in water since it's density is greater than that of water which is 1.0 g/cm³
Hope this helps you
If all of the bonding electrons in a molecule are bonded in two-hybrid sp orbitals are likely to have a linear shape.
<h3>What are sp orbitals?</h3>
One of a set of hybrid orbitals is produced when one s orbital and one p orbital is combined mathematically to form two new equivalent, perpendicular orbitals.
A linear molecule is one in which the atoms are arranged in a straight line (less than a 180° angle). The sp hybridization occurs at the central atom of molecules with linear electron-pair geometries.
Carbon dioxide (O=C=O) and beryllium hydride
are examples of linear electron pairs and molecular geometry.
Hence, option A is correct.
Learn more about the sp orbitals here:
brainly.com/question/10472619
#SPJ1
Answer:
For pure water, the values of [H3O+] and [OH-] are equal and thus their values are both 1.0 x 10-7. If there is an equal amount of acid and base present in any solution, the solution is called "neutral" and the pH of the solution is 7. ... The sum of the pH and pOH must always equal 14.
Explanation:
Answer:
3.3765 Mol O2
Explanation:
There is no work for this problem