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Olenka [21]
3 years ago
7

20. Solve 4 - 2(b - 6) = 12b = 2b = 12b = -2b = -10​

Mathematics
2 answers:
spayn [35]3 years ago
4 0

Answer:

b=2

Step-by-step explanation:

4-2b-2*(-6)=12

4-2b+12=12

-12            -12

4-2b=0

+2b    +2b

4=2b

:2   :2

b=4:2

b=2

Maurinko [17]3 years ago
3 0

Answer:

<h2>b=2</h2>

Option A is the correct option.

Solution,

4 - 2(b - 6) = 12 \\ or \: 4 - 2b + 12 = 12 \\ or \: 4 + 12 - 2b = 12 \\ or \: 16 - 2b = 12 \\ or \:  - 2b = 12 - 16 \\ or \:  - 2b = -  4 \\ or \: b =  \frac{ - 4}{ - 2}  \\ b = 2

Hope this helps...

Good luck on your assignment..

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The Answer: x= −12/7

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If i hiked 5 2/10 kilometers in one weekend and the next week i hike 9/10 kilometer more than then the week before how many kilo
goldfiish [28.3K]

Answer:

6\frac{1}{10} kilometers

Step-by-step explanation:

From the given question, it can be inferred that;

In the first weekend, distance covered = 5\frac{2}{10} kilometers.

But in the second week or following weekend, I hike \frac{9}{10} more than the first week implies that, total distance covered in the second week = distance covered in the first week + \frac{9}{10}

                                            = 5\frac{2}{10} + \frac{9}{10}

                                            = \frac{52}{10} + \frac{9}{10}

                                            = \frac{52 + 9}{10}

                                            = \frac{61}{10}

                                            = 6\frac{1}{10}

Therefore, the total distance walked in the second week is 6\frac{1}{10} kilometers.

7 0
4 years ago
If 4/5 x blank = 2/5, what is blank
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So we know nothing about blank so we can infer that’s our X in this case

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1/2

8 0
3 years ago
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Answer:

6/7

Step-by-step explanation:

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7 0
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Drag the tiles to the correct boxes to complete the pairs.
Elza [17]

Answer:

Part 1)  -7 →  \dfrac{y^2-y+6}{-2(y+7)}  

Part 2) 3/2 → \dfrac{y^2-2y+1}{2y-3} 

Part 3) 1  → \dfrac{5y^2-6y+1}{-5(y-1)}

Part 4) -1/4 → \dfrac{y(y+5)}{4y+1}

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

we know that

To find out the non permissible replacements for y, equate the denominator of each expression equal to 0.

step 1    

we have

\dfrac{y^2-2y+1}{2y-3}

Equate (2y-3) equal to 0.

2y-3=0

solve for y

Adds 3 both sides.

2y=3

Divide both sides by 2.

y=\dfrac{3}{2}

therefore

3/2 is the non permissible replacement for y.

step 2

we have

\dfrac{y(y+5)}{4y+1}

Equate (4y+1) equal to 0.

4y+1=0

Subtract 1 both sides

4y=-1

Divide by 4 both sides

y=-\dfrac{1}{4}

therefore

-1/4 is the non permissible replacement for y.

step 3

we have

\dfrac{5y^2-6y+1}{-5(y-1)}

Equate -5(y-1) equal to 0.

-5(y-1)=0

Divide by -5 both sides

y-1=0

Adds 1 both sides

y=1

therefore

1 is the non permissible replacement for y.

step 4

we have

\dfrac{y^2-y+6}{-2(y+7)}

Equate -2(y+7) equal to 0.

-2(y+7)=0

Divide by -2 both sides

y+7=0

Subtract 7 both sides

y=-7

therefore

-7 is the non permissible replacement for y

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3 years ago
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