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3 years ago

7

20. Solve 4 - 2(b - 6) = 12b = 2b = 12b = -2b = -10

2 answers:

spayn [35]3 years ago

4 0

Answer:

b=2

Step-by-step explanation:

4-2b-2*(-6)=12

4-2b+12=12

-12 -12

4-2b=0

+2b +2b

4=2b

:2 :2

b=4:2

b=2

Maurinko [17]3 years ago

3 0

Answer:

<h2>b=2</h2>

Option A is the correct option.

Solution,

$4 - 2(b - 6) = 12 \\ or \: 4 - 2b + 12 = 12 \\ or \: 4 + 12 - 2b = 12 \\ or \: 16 - 2b = 12 \\ or \: - 2b = 12 - 16 \\ or \: - 2b = - 4 \\ or \: b = \frac{ - 4}{ - 2} \\ b = 2$

Hope this helps...

Good luck on your assignment..

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Answer:

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Step-by-step explanation:

From the given question, it can be inferred that;

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Therefore, the total distance walked in the second week is 6 $\frac{1}{10}$ kilometers.

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4 years ago

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3 years ago

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3 years ago

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Answer:

Part 1) -7 → $\dfrac{y^2-y+6}{-2(y+7)}$

Part 2) 3/2 → $\dfrac{y^2-2y+1}{2y-3}$

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Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

we know that

To find out the non permissible replacements for y, equate the denominator of each expression equal to 0.

step 1

we have

$\dfrac{y^2-2y+1}{2y-3}$

Equate (2y-3) equal to 0.

$2y-3=0$

solve for y

Adds 3 both sides.

$2y=3$

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$y=\dfrac{3}{2}$

therefore

3/2 is the non permissible replacement for y.

step 2

we have

$\dfrac{y(y+5)}{4y+1}$

Equate (4y+1) equal to 0.

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Subtract 1 both sides

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Divide by 4 both sides

$y=-\dfrac{1}{4}$

therefore

-1/4 is the non permissible replacement for y.

step 3

we have

$\dfrac{5y^2-6y+1}{-5(y-1)}$

Equate -5(y-1) equal to 0.

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therefore

1 is the non permissible replacement for y.

step 4

we have

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Equate -2(y+7) equal to 0.

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Divide by -2 both sides

$y+7=0$

Subtract 7 both sides

$y=-7$

therefore

-7 is the non permissible replacement for y

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3 years ago