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Ket [755]
2 years ago
14

Find the area of the triangle 19cm 15cm 12cm

Mathematics
1 answer:
777dan777 [17]2 years ago
4 0

Answer:

Step-by-step explanation:

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It's a PEMDAS question
monitta

[3 * (2 + 4)] - 4

  • Solve inside the brackets first.
  • Solve the parentheses inside the brackets, (2 + 4).

[3 * (6)] - 4

  • Now solve 3 * 6.

18 - 4

  • 18 - 4 = 14, so your answer is:
<h3>14</h3>
4 0
3 years ago
Read 2 more answers
PLZ HELP QUICK!!!
Viktor [21]

Answer:

9-8

Step-by-step explanation:

60 divided by 7 is 8.5

4 0
3 years ago
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What is the length of the arch CH
Yakvenalex [24]

Answer:

147°

Step-by-step explanation:

The measure of arc CH is equal to the central angle it sees

the angles arc AH sees are BAC and CAH so the length of arc AH would be the sum of these two angles

90° + 57° = 147°

3 0
3 years ago
What value will make the equation true -21-?=1.5
AfilCa [17]

Answer: ? = -22.5

Step-by-step explanation:

Using a negative number to replace the ? turns the minus into a plus sign.

-21 - (-22.5) = 1.5 is the same as -21 + 22.5 = 1.5

6 0
3 years ago
Let f(x) be a polynomial such that f(cos θ) = cos(4) θ for all θ. Find f(x). (This is essentially the same as finding cos(4) θ i
Galina-37 [17]

Answer:

f(x) = 8x⁴-8x²+1

Step-by-step explanation:

I will assume that f(cos θ) = cos(4θ). Otherwise, f would not be a polynomial. lets divide cos(4θ) in an expression depending on cos(θ). We use this properties

  • cos(2a) = cos²(a) - sin²(b)
  • sin(2a) = 2sin(a)cos(a)
  • sin²(a) = 1-cos²(a)

cos(4θ) = cos(2 * (2θ) ) = cos²(2θ) - sin²(2θ) = [ cos²(θ)-sin²(θ) ]² - [2cos(θ)sin(θ)]² = [cos²(θ) - ( 1 - cos²(θ) ) ]² - 4cos²(θ)sin²(θ) = [2cos²(θ)-1]² - 4cos²(θ) (1 - cos²(θ) ) = 4 cos⁴(θ) - 4 cos²(θ) + 1 - 4 cos²(θ) + 4 cos⁴(θ) = 8cos⁴(θ) - 8 cos²(θ) + 1

Thus f(cos(θ)) = 8 cos⁴(θ) - 8 cos²(θ) + 1, and, as a result

f(x) = 8x⁴-8x²+1.

5 0
3 years ago
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