The graph is attached.
We first graph the point where his catch reached the surface, (35, 0). Since it travels upward at a constant rate, the graph will be linear. We also need to know where it starts (what depth it is at when he begins reeling it in). We can use the formula d=rt as a template for our function. d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.
To find how far the catch had to travel to reach the surface, we set up our equation as:
d = 0.1(35)
This will tell us how much distance it traveled in 35 seconds. 0.1(35)=3.5, so the catch started 3.5m under water. It then travels up at 0.1 m per second.
→ 
8 and 10 can both be divided by 2. So, 8 ÷ 2 is 4 and 10 ÷ 2 is 5.
Hope this helps :)
3^8=6,561
6,561 •3=19,683
The highest altitude of an altocumulus cloud is 19,683 feet.
Answer:
9.75 hours
Step-by-step explanation:
If Rob drove 35% of the time and Mark drove the remainder of the time, the total is 100 %
100-35 = 65
so Mark drove 65% of the time
The total time driven was 15 hours, so we multiply the total time driven by the percentage of time that Mark drove to find the number of hours that Mark drove.
15 * 65%
15*.65
9.75 hours