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vichka [17]
3 years ago
15

find the value of c that makes each trinomial a perfect square. then write the trinomial as a perfect square. the equation , x^2

+11x+c ...?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0
Therefore, the value of C should be (11/2)^2

<span>To square a fraction, take the square of the numerator and put it over the square of the denominator. So since 11^2=121 and 2^2=4, (11/2)^2
(11)^2/(2)^2=121/4
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Tracy has a cell phone plan that provides 250 free minutes each month for a flat rate of $29.
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Answer:

250 minutes with the flat rate of $29.

x\leq 250

x would be the number of minutes called.

x-250

Tracy would be charged by $0.35 per minute.

f(x)=29\\ 0\leq x\leq 250

f(x)=0.35(x-250)+29,\\250\leq x\leq ∞

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What is the least common multiple<br> of 1/3 5/8 1/2?
joja [24]

Answer: The answer is 16.

Step-by-step explanation:

The least common denominator means the same as least common multiple.

3, 6, 9, 12, 16

8, 16

2, 4, 6, 8, 10, 12, 14, 16y-step explanation:

7 0
2 years ago
The 90% confidence interval for the mean one-way commuting time in New York City is
Zinaida [17]

Answer:

95% provides more information

Step-by-step explanation:

The confidence interval is obtained by using the relation :

Xbar ± Zcritical * σ/√n

(Xbar - (Zcritical * σ/√n)) = 5.22 - - - (1)

(Xbar + (Zcritical * σ/√n)) = 5.98 - - (2)

Adding (1) and (2)

2xbar = 5.22 + 5.98

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xbar = 11.2 / 2 = 5.6

Margin of Error :

Xbar - lower C.I = Zcritical * σ/√n

Zcritical at 90% = 1.645

5.6 - 5.22 = 1.645 * (σ/√n)

0.38 = 1.645 * (σ/√n)

(σ/√n) = 0.38 / 1.645 = 0.231

Therefore, using the se parameters to construct at 95%

Zcritical at 95% = 1.96

Margin of Error = Zcritical * σ/√n

Margin of Error = 1.96 * 0.231 = 0.45276

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C. I = (5.147 ; 6.053)

Hence, 95% confidence interval provides more information as it is wider.

3 0
3 years ago
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