HELP!!!!!!!!!!! PLEASE WILL MAKE BRAINLIEST AND 25 POINTS PLEASE HELP!!!!!!!!!!!!!!!!!!!!!Which statements are true about the or
dered pair (−3, 1) and the system of equations?
{x−4y=63x+y=−8
Select each correct answer.
The ordered pair (−3, 1) is a solution to the first equation because it makes the first equation true.
The ordered pair (−3, 1) is a solution to the second equation because it makes the second equation true.
The ordered pair (−3, 1) is not a solution to the system because it makes at least one of the equations false.
The ordered pair (−3, 1) is a solution to the system because it makes both equations true.
{x−4y=63x+y=−8
Select each correct answer.
The ordered pair (−3, 1) is a solution to the first equation because it makes the first equation true.
The ordered pair (−3, 1) is a solution to the second equation because it makes the second equation true.
The ordered pair (−3, 1) is not a solution to the system because it makes at least one of the equations false.
The ordered pair (−3, 1) is a solution to the system because it makes both equations true.
1 answer:
You might be interested in
9514 1404 393
Answer:
m ≥ -√5
Step-by-step explanation:
If g(x) = f(|x|) for x∈i, then g(x) = f(x) for x∈ℝ: x ≥ 0.
f'(x) is 5th-degree, so f(x) is 6th-degree, meaning it is generally U-shaped. Since we're only concerned with x ≥ 0, we want to make sure f'(x) has no real zeros of odd multiplicity such that x > 0. The given factors of f'(x) make it have real zeros at x = -3 and x = -1.
For the last factor, (x² +2mx +5) to have no positive real zeros of odd multiplicity, we must have m ≥ 0 or the discriminant ≤ 0. The discriminant is ...
d = b² -4ac = (2m)² -4(1)(5) = 4m² -20 . . . . . discriminant of the last factor
d ≤ 0 . . . . . . . . . . the condition for no real zeros
4m² -20 ≤ 0
m² -5 ≤ 0 . . . . . . divide by 4
m² ≤ 5 . . . . . . . . .add 5
|m| ≤ √5 . . . . . . . take the square root
This tells us there will be a positive real zero of multiplicity 2 in f'(x) when m = -√5, and there will be no positive real zeros for -√5 < m < 0
There will be no odd-multiplicity positive real zeros in the derivative function f'(x) as long as m ≥ -√5. This means the slope of f(x) is non-negative for x ≥ 0, hence f(|x|) has its only minimum at x=0.
_____
<em>Additional comment</em>
The multiplicity of the zeros of f'(x) is important because the derivative will only change sign where the multiplicity is odd. When the discriminant of (x²+2mx+5) is zero, the associated positive real zero will have multiplicity 2, hence f'(x) will not change sign there.
Answer:
29 cans
Step-by-step explanation:
To solve this problem we must use Heron's formula; A =
S = 1/2 the perimeter of the given triangle
a, b, c = the measurements of the three given sides
The first step to solving this question is first finding the perimeter.
P = 65m + 74m + 67m
P = 206m
Now that we have our perimeter, we must divide P by 2 to get S.
S = 206/2
S = 103
Now we plug our numbers into Heron's formula.
A =
A =
A =
A =
A =
Find the square root of this number.
A ≈ 2021.43909134... m²
If a can of paint covers 70 square meters, then you will need to figure out how many cans you need. This can be done by dividing the overall area of the triangle by the area that a single can of paint can cover.
= 28.8777013049...
We know we can't buy 28.87... of a can (people simply do not sell parts of cans or half-full containers... unless its a bag of lays chips and their 80% air nonsense...) so we must round up to the nearest whole number.
28.87... = 29
Thus we finally have our answer: 29 cans of paint!