Please break down this problem 4x^3+103=0
1 answer:
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Answer:
sinΘ =
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 ( subtract cos²x from both sides )
sin²x = 1 - cos²x ( take square root of both sides )
sinx = ±
given
cosΘ = - , then
sinΘ = ±
= ±
= ±
= ±
since Θ is in quadrant II where sinΘ > 0 , then
sinΘ =
