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bogdanovich [222]
3 years ago
15

Please help me with this

Mathematics
2 answers:
Rasek [7]3 years ago
7 0
Y=x :)) hoping this helped even though i’m like very late-
DENIUS [597]3 years ago
6 0

Answer:

y=x

Step-by-step explanation:

Both x and y are the same so y=x or x=y.

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05) A polynomial function f of degree(6) whose coefficients are real numbers has the zeros i, 4-i,2+i . Find the remaining zeros
arlik [135]

The degree of the polynomial function f is the number of zeros function f has.

The remaining zeros of the polynomial function are -i, 4 + i and 2 - i

<h3>How to determine the remaining zeros</h3>

The degrees of the polynomial is given as;

Degree = 6

The zeros are given as:

i, 4-i,2+i

The above numbers are complex numbers.

This means that, their conjugates are also zeros of the polynomial

Their conjugates are -i, 4 + i and 2 - i

Hence, the remaining zeros of the polynomial function are -i, 4 + i and 2 - i

Read more about polynomials at:

brainly.com/question/4142886

3 0
2 years ago
Eh whats the answer. thankssssssssss
sergey [27]

Answer:

Yea.. Its C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
0.5x - 4&lt; 1
Pie

Answer:

5.0-1...............

8 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
Initially, the ratio of Ed’s toy cars to Pete’s toy cars was 5:2. After Ed gave 30 toy cars to Pete, they each had an equal numb
Burka [1]
So here is the answer. Initially, Ed's toy cars compared to Pete's toy cars was 5:2. So for every 5 cars that Ed has, Pete has 2. Now that Ed gave 30 cars to Pete. So here it goes. The total number of ratio units is 5+2=7, so each will have an equal number if they both have 3.5 ratio units. That is, if Ed transfers to Pete 1.5 ratio units, their car counts will be equal. Thus 1.5 ratio units = 30 cars, or 1 ratio unit = 20 cars. Therefore, this makes <span> 7*20 cars = 140 cars.
</span>Hope this helps.
6 0
3 years ago
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