This is an incomplete question, here is a complete question.
A 6.55 g sample of aniline
molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature rose by 32.9°C, use the information below to determine the heat capacity of the calorimeter.
![4C_6H_5NH_2(l)+35O_2(g)\rightarrow 24CO_2(g)+14H_2O(g)+4NO_2(g)](https://tex.z-dn.net/?f=4C_6H_5NH_2%28l%29%2B35O_2%28g%29%5Crightarrow%2024CO_2%28g%29%2B14H_2O%28g%29%2B4NO_2%28g%29)
ΔH°rxn = -1.28 × 10⁴ kJ
Answer : The heat capacity of the calorimeter is, ![6.84kJ/^oC](https://tex.z-dn.net/?f=6.84kJ%2F%5EoC)
Explanation :
First we have to calculate the moles of aniline.
![\text{Moles of aniline}=\frac{\text{Mass of aniline}}{\text{Molar mass of aniline}}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20aniline%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20aniline%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20aniline%7D%7D)
![\text{Moles of aniline}=\frac{6.55g}{93.13g/mol}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20aniline%7D%3D%5Cfrac%7B6.55g%7D%7B93.13g%2Fmol%7D)
![\text{Moles of aniline}=0.0703mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20aniline%7D%3D0.0703mol)
Now we have to calculate the heat releases.
As, 4 mole of aniline on combustion to releases heat = ![1.28\times 10^4kJ](https://tex.z-dn.net/?f=1.28%5Ctimes%2010%5E4kJ)
So, 0.0703 mole of aniline on combustion to releases heat = ![\frac{0.0703}{4}\times 1.28\times 10^4kJ=224.96kJ](https://tex.z-dn.net/?f=%5Cfrac%7B0.0703%7D%7B4%7D%5Ctimes%201.28%5Ctimes%2010%5E4kJ%3D224.96kJ)
Now we have to calculate the heat capacity of the calorimeter.
![\text{Heat capacity of the calorimeter}=\frac{\text{Heat releases}}{\text{Change in temperature}}](https://tex.z-dn.net/?f=%5Ctext%7BHeat%20capacity%20of%20the%20calorimeter%7D%3D%5Cfrac%7B%5Ctext%7BHeat%20releases%7D%7D%7B%5Ctext%7BChange%20in%20temperature%7D%7D)
![\text{Heat capacity of the calorimeter}=\frac{224.96kJ}{32.9^oC}](https://tex.z-dn.net/?f=%5Ctext%7BHeat%20capacity%20of%20the%20calorimeter%7D%3D%5Cfrac%7B224.96kJ%7D%7B32.9%5EoC%7D)
![\text{Heat capacity of the calorimeter}=6.84kJ/^oC](https://tex.z-dn.net/?f=%5Ctext%7BHeat%20capacity%20of%20the%20calorimeter%7D%3D6.84kJ%2F%5EoC)
Thus, the heat capacity of the calorimeter is, ![6.84kJ/^oC](https://tex.z-dn.net/?f=6.84kJ%2F%5EoC)