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galben [10]
3 years ago
9

The cellular process in which materials are moved across a membrane from an area of low concentration to an area of high concent

ration is called
a.osmosis.
b.simple diffusion.
c.active transport.
d.passive transport.
Biology
2 answers:
Sidana [21]3 years ago
7 0
The best answer is C. Active Transport
babymother [125]3 years ago
5 0

Answer:

C) Active Transport

Explanation:

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Identify the products of cellular respiration and photosynthesis
icang [17]

<u>Answer:</u>

Cellular respiration:

C _ 6 H _ { 1 2 } O _ 6 \implies 6 C O _ 2 + 6 H _ 2 O + 3 8 A T P

Photosynthesis:

6CO_2+12H_2O \implies C_6H_{12}O_6 +6O_2+6H_2O

<u>Explanation:</u>

The process of breaking down the sugar into a form of usable energy by the cell is called cellular respiration.

It can be shown by an equation as:

C _ 6 H _ { 1 2 } O _ 6 \implies 6 C O _ 2 + 6 H _ 2 O + 3 8 A T P

So the product here includes ATP which is the energy along with carbon dioxide and water.

While photosynthesis is the process where sunlight is used to convert the carbon dioxide into sugars to be used as energy.

6CO_2+12H_2O \implies C_6H_{12}O_6 +6O_2+6H_2O

Here the products are sugars, oxygen and water.

7 0
3 years ago
Do you think that Humanity should make the effort to colonize space?
laila [671]

Answer:

Yes

Explanation:

Human space exploration helps to address fundamental questions about our place in the Universe and the history of our solar system. Through addressing the challenges related to human space exploration we expand technology, create new industries, and help to foster a peaceful connection with other nations.

6 0
3 years ago
Read 2 more answers
What is the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mM?
Doss [256]

Answer:

50 micro mol/min

Explanation:

So, we have the following parameters which are going to help us in solving this particular Question or problem;

=> For the wild type enzyme, the value for the Maximum velocity = 100 micromol/min.

=> For the mutant type enzyme, the value for the Maximum velocity = 1 micromol/min.

So, we can determine or calculate the value for the initial velocity for each of the enzyme type by using the formula below;

Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Therefore, for the wild type enzyme; the Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Initial velocity =( 10mM × 100micromol/min) ÷ ( 10mM + 10 mM ) = 50 micro mol/min.

Initial velocity for the wild type enzyme = 50 micro mol/min.

8 0
3 years ago
Which statements are true for dna and rna? check all that apply?
LekaFEV [45]
Since there are no given choices, I would just compare and contrast DNA and RNA. These are the two types of nucleic acids in the human body. The structural unit of nucleic acids are composed of repeating units of monomers called nucleotides. Nucelotides are composed of three functional groups: sugars which are specifically pentoses (5-Carbon sugars), phosphate group and nitrogenous base.

Now, the RNA and DNA differ in the composition of these sugars and the bases. Based on the nitrogenous bases and sugar, the DNA has a deoxyribose as the sugar and its 4 bases are adenine, guanine, cytosine and thymine. For RNA, the sugar is ribose while its 4 bases are <span>adenine, guanine, cytosine, and uracil.

They also differ in their structure. </span>DNA is a double stranded β-helix with a long chain of nucleotides. RNA is composed of a shorter chain with a single strand α-helix structure.

Lastly, they differ in their functions. T<span>he DNA is responsible for storing the genetic information while the RNA is responsible for transporting the genetic information to the ribosomes which synthesize proteins.</span>
5 0
3 years ago
A pea plant with purple flowers (and unknown genotype) is crossed with a pea plant with white flowers. one-half of the offspring
Archy [21]
The genotypes of the parents are Aa (heterozygous) and aa (recessive homozygous).  
 For example:  
 If the purple flower is dominant phenotype, then A is a dominant allele for it and Aa is a genotype which will give the purple colour.
In this case, white flower is recessive phenotype with aa genotype.
If we cross Aa x aa
<span>The offspring is going to be Aa Aa aa aa (half purple and half white)</span>
8 0
3 years ago
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