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iren [92.7K]
3 years ago
13

Hey, can someone help me with this?

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

1/2 ÷ 4 = 1/8

Step-by-step explanation:

The way to think about this is you want to divide how much you have by how many people there are.

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Five snails are having a race. The snail's speeds are given in the table. Which two snails are going the same rate of speed?
kobusy [5.1K]

Answer:

2 1/5 for alice

4 3/14 for Bert

5 for Carl

5 for Eva

5 1/2 for Dennis

Carl and Eva

4 0
3 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
4 years ago
Which of the following rational functions is graphed below? ​
Shalnov [3]
You didn’t put your whole question so I can’t help sorry :(((((((((((
4 0
3 years ago
Jonah’s Restaurant reports net income of $20,000 during the year 2015. It distributes a dividend of $6,000 to its shareholders.
AlekseyPX
Retention ratio = (net income - dividends) / net income

retention ratio = (20,000 - 6000) / 20000 = 14,000/20,000 = 0.7 = 70%
3 0
4 years ago
A rectangular prism with a volume of 5 cubic units is filled with cubes with side lengths of 1/3
pishuonlain [190]

Step-by-step explanation:The volume of each cube = (side)^3 = (1/3)^3 = 1/27 cubic units

The number of cubes that will fill the prism =

Vol of prism 4

__________ = _____ = 4 * 27 = 108 cubes

Vol of cube (1/27)

5 0
3 years ago
Read 2 more answers
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