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2 years ago

15

A human red blood cell is about 0.00000 8 in diameter. Put this number in scientific notation.

1 answer:

GalinKa [24]2 years ago

8 0

Answer:

$\large\boxed{0.000008=8\cdot10^{-6}}$

Step-by-step explanation:

The scientific notation:

$a\cdot10^k$

where 1 ≤ a < 10 and k ∈ Z.

0.000008

You must move the comma 6 places to the right.

$0\underbrace{.000008}_{6\rightarrow}=8\cdot10^{-6}$

$0.000008=\dfrac{8}{1,000,000}=8\cdot10^{-6}$

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vampirchik [111]

Step-by-step explanation:

see below

$\longrightarrow \: \frac{4}{5} - \frac{3}{10}$

$\longrightarrow \: \frac{8 - 3}{10}$

$\longrightarrow \: \cancel{\frac{5}{10} }$

$\longrightarrow \: \frac{1}{2}$

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2 years ago

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Which of the following equations has the solution x= all real numbers?

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The answer is C
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3 years ago

In ΔDEF, what is sin D, in simplified form?

Igoryamba

Answer: second option.

Step-by-step explanation:

You must apply $sin\alpha=\frac{opposite}{hypotenuse}$

Then, given the right triangle and the angle D, the opposite side and the hypotenuse of the triangle are the following:

$opposite=20\\hypotenuse=25$

Therefore, when you substitute values, you have:

$sinD=\frac{20}{25}$

Reduce the fraction, then you obtain:

$sinD=\frac{4}{5}$

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3 years ago

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Cindy spends $85 a month on her cell phone plan. She has saved $1,105 to pay her phone bill. How many months will Cindy be able

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Step-by-step explanation:

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3 years ago

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Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

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3 years ago