Question

Calculate the space that NH3 occupies at 40 degrees Celsius and 910 torr. There are 955 grams of the gas

Answer 1

Answer:

The space that NH3 occupies is 1,205L

Explanation:

Using the ideal gas law we can find the volume of the gas

$PV=nRT$

Where:

• P is the pressure of the gas in Torr

• V is the volume of the gas in Liters

• n are the moles of gas

• T is the temperature of the gas in Kelvin

• R is the gas constant (62,36 L.Torr/K.mol)

First, we convert the temperature to kelvin, and find the moles of gas using the mass and molecular weight of NH3

T(K)= °C + 273,15= 40 + 273= 313K

$n=\frac{Mass(g)}{Molecular Weight(g/mol)} \\\\n= \frac{955g}{17g/mol} = 56,18mol$

Now we find the volume with the ideal gas law

$V=\frac{nRT}{P} \\\\V=\frac{(56,18mol)(62,36L.atm/K.mol)(313,15K)}{910Torr} \\\\V=1,205L$