Answer:
A volume of 236 L and a temperature of 10.0 ° C has a pressure of 25.3 kPa.
Explanation:
Boyle's law says that "The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure." Boyle's law is expressed mathematically as: P * V = k
Gay-Lussac's law can be expressed mathematically as follows:
This law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.
Finally, Charles's Law consists of the relationship between the volume and the temperature of a certain amount of ideal gas, which is kept at a constant pressure. This law is a law that says that when the amount of gas and pressure are kept constant, the quotient between the volume and the temperature will always have the same value:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
Studying two different states, an initial state and a final state, you have:
In this case:
- P1= 50.7 kPa
- V1= 120 L
- T1= 15 C= 288 K (being 0 C= 273 K)
- P2= ?
- V2= 236 L
- T2= 10 C= 283 K
Replacing:
Solving:
P2= 25.3 kPa
<u><em>A volume of 236 L and a temperature of 10.0 ° C has a pressure of 25.3 kPa.</em></u>
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mass h
<h3>
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Explanation:
molar mass is equal to number of mass over moles we take 14.19 over17 molar mass of ammammonium equals 0.8347 incase of moles. 1H=1Nh3 ,so. n.H=0.8347 Mr=2 ,M.H=? Mr=m/n. 0.8347x2=1.669grams
Answer:
See the answer below
Explanation:
From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.
Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.
Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.
<em>In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover. </em>
This formula indicates that a molecule of acetic acid (Figure 6) contains two<span> carbon atoms, </span>four<span> hydrogen atoms, and </span>two<span> oxygen atoms. The ratio of atoms is 2:</span>4<span>:2. I hope this helps</span>
