Cl2+2KI→2KCl + I2 is an example of which type of reaction?

1. The actual yield of a product in a reaction was measured as 1.20 g. If the theoretical yield of the product for the reaction

n200080 [17]

<h3>1. <u>Answer;</u></h3>

Percentage yield = 65.9%

<h3><u>Explanation;</u></h3>

Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.

Therefore;

Percentage yield = Actual yield/theoretical yield × 100%

= (1.20 g/1.82 g) × 100%

= 65.9%

<h3 /><h3>2. <u>Answer;</u></h3>

The amount of measured yield over calculated yield

<h3>Explanation;</h3>

Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
The actual yield is the actual amount produced when the experiment or reaction is carried out.
Theoretical yield is the calculated or expected amount of the product. It is based on the limiting reactant.

<h3>3. <u>Answer</u>;</h3>

= 37.71 g

<h3><u>Explanation;</u></h3>

The balanced equation is:

2 Na + Cl₂ → 2 NaCl.

From the balanced equation:

2.0 moles of Na reacts with 1.0 mole of chlorine gas to give 2.0 moles of NaCl.

The number of moles of Na = mass/atomic mass),

n = (17.25 g / 22.989 g/mole of Na)

= 0.75 moles

Thus;

Using cross multiplication and from the equation:

2.0 moles of Na → 2.0 moles of NaCl

0.75 moles of Na → 0.75 moles of NaCl

Therefore;

The mass of the produced NaCl (m = n x molar mass)

m = (0.75 mole x 58.443 g/mole of NaCl)

= 43.85 g.

This is the yield if the percentage of yield is 100%, but the percentage yield of the reaction is 86%.

Hence;

The actual yield = (43.85 g) (86/100)

= 37.71 g.

<h3>4. <u>Answer;</u></h3>

Oxygen and hydrogen molecules will mix because of random movement of their molecules.

<h3><u>Explanation;</u></h3>

Both gasses will diffuse into the other jar until the molecules are well distributed into both containers.
Diffusion is the movement of molecules from a point of high concentration to areas of low concentration until equilibrium is attained.
The mixture of gases will have a partial pressure that is equal to the sum of the partial pressures of the component gases.

5 0

3 years ago

Shay constructed a scientific model of the carbon cycle. She included plants, animals, industry, fossil fuels, and the atmospher

LenKa [72]

Answer:

no one can answer your question because you have shown no arrows.

3 0

3 years ago

Based on the Periodic Table, explain why Na and Khave similar chemical properties

sasho [114]

The Group 1 elements, which include lithium (Li), sodium<span> (</span>Na) and potassium (K<span>) are also known as the alkali metals. They all </span>have<span> one electron in the outer shell and so they </span>have similar properties<span>.</span>

3 0

3 years ago

For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.

Yakvenalex [24]

Data Given:
Change in Entropy =  ΔH = 120.5 kJ = 1.20 × 10⁵ J

Temperature = T = 298 K

Change in Entropy =  ΔS = 758.2 J/K

Using Formula,
  ΔG =  ΔH - T ΔS
Putting Values,
  ΔG = (1.20 × 10⁵ J) - (298 K × 758.2 J/K)

  ΔG = -1.059 × 10⁵ J

  ΔG = -105.94 kJ

8 0

3 years ago

Even at high T, the formation of NO is not favored:

Readme [11.4K]

Answer:

3,16x10⁻³M

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO(g). The kc is defined as:

kc = [NO]² / [N₂] [O₂] = 4,10x10⁻⁴ <em>(1)</em>

If you add in a 1,0L container 0,25 mol of N₂ and 0,10 mol of O₂, concentrations in equilibrium will be:

[N₂] = 0,25M - x

[O₂] = 0,10M - x

[NO] = 2x

Replacing in (1):

[2X]² / [0,25-x] [0,10-x] = 4,10x10⁻⁴

[2X]² / 0,025 - 0,35x + x²= 4,10x10⁻⁴

4X² = 4,10x10⁻⁴x² - 1,435x10⁻⁴x + 1,025x10⁻⁵

3,99959x² + 1,435x10⁻⁴x - 1,025x10⁻⁵ = 0

Solving for x:

x = -0,0016 (<em>Wrong answer, there is no negative concentrations</em>)

x = 0,00158 (<em>Right answer</em>)

As molar concentration of NO in equilibrium is 2x:

[NO] = 2x = 2×0,00158 = <em>3,16x10⁻³M</em>

I hope it helps!

6 0

3 years ago