C: One plate is going underneath the other plate and sinking into the soft rock below.
Explanation:
Where plates are moving towards each other they are said to converging, and are called convergent margins.
The lithosphere is broken into series of slabs called plates. The plates moves on the weak and relatively soft asthenosphere below.
Plates have different motion. At some places, they move apart and they are said to be divergent.
When plates moves towards each other, they are convergent. At a convergent margin, a plate collides with another thereby causing the denser plate usually the oceanic plate to subduct into the asthenosphere. In some other cases, the plates can collide and build upward.
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Answer:
6.25gm
half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times
Explanation:
Answer : The half-life at this temperature is, 3.28 s
Explanation :
To calculate the half-life for second order the expression will be:
![t_{1/2}=\frac{1}{k\times [A_o]}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5Ctimes%20%5BA_o%5D%7D)
When,
= half-life = ?
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial concentration = 0.45 M
k = rate constant = 
Now put all the given values in the above formula, we get:
Therefore, the half-life at this temperature is, 3.28 s
Answer:
-470.4 kJ/mol
Explanation:
Balanced reactions equations are as follows.
CaC2 (s) + 2H2O (l) â C2H2 (g) + CaOH2 (s) ÎH=â414.kJ
6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ
To get the 6 C2H2 we need to multiply first equation by 6
Then we get
6CaC2 (s) + 12H2O (l) â 6C2H2 (g) + 6CaOH2 (s) ÎH=â414.kJ * 6 = -2484 kJ
6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ
So the total energy produced = -2484 kJ + 132.0 kJ = -2352 kJ
This amount of energy is given out for the 5 moles of acid
So lets convert it for 1 mol
-2352 kJ * 1 mol / 5 mol = -470.4 kJ/mol
So the delta H of reaction for the formation of the acrylic acid is -470.4 kJ/mol
