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serg [7]
3 years ago
6

Write y=-3x^2-18x-31 in vertex form

Mathematics
2 answers:
Ahat [919]3 years ago
8 0
-3(x+(3))^2-4 is the answer

MissTica3 years ago
5 0
Get it into f(x)=a(x-h)²+k form
basically complete the square

so
steps
1. isolate x terms
2. factor out coefient of x^2 term
3. take 1/2 of linear coefient (x term) and square it and add negative and positive inside of parenthasees
4. factor perfect square
5. expand
6. bow


so
f(x)=-3x²-18x-31
group
f(x)=(-3x²-18x)-31
undistribute coefient
f(x)=-3(x²+6x)-31
take 1/2 of 6 and square it (6/2=3, 3²=9), add positive and negative of it inside
f(x)=-3(x²+6x+9-9)-31
factor perfect square
f(x)=-3((x+3)²-9)-31
expand/distribue
f(x)=-3(x+3)²+27-31
f(x)=-3(x+3)²-4


answer is
f(x)=-3(x+3)²-4
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A particle begins at point (1, 2) and is moving along the line segment joining (1, 2) to (3, 4). Initially, what is the rate of
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Answer:

Initially, that is, at (1,2), the rate of increase of the function in the direction given = 0

Hence the function is neither increasing nor decreasing initially in the given direction.

Step-by-step explanation:

f(x,y) = 2x² - y²

Rate of Change of the function = ∇f = (fₓ, fᵧ)

And we're told to find the rate of change in a particular direction = ∇f.û

We first obtain the unit vector in that direction, û

Direction = (3,4) - (1,2) = (2,2)

Uni vector = vector/magnitude

Vector = 2î + 2j

magnitude = √(2² + 2²) = √8 = 2 √2

(2î + 2j)/(2√2) = (1/√2)î + (1/√2)j = û

Unit vector in the direction = (1/√2, 1/√2)

f = 2x² - y²

At (1,2)

fₓ = ∂f/∂x = 4x = 4

fᵧ = ∂f/∂y = -2y = -4

∇f = (4,-4)

∇f.û = (4î - 4j).((1/√2)î + (1/√2)j) = (4/√2) - (4/√2) = 0

If it was positive, then the function is increasing, if it was negative, the function is decreasing. Zero means neither of them.

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7 0
3 years ago
Solve each system of equations by writing a new system that eliminates one of the variables.
Rufina [12.5K]

Answer:

x=33\\y=-41

Step-by-step explanation:

Let:

2x+y=25\hspace{5}(1)\\and\\4x+3y=9\hspace{5}(2)

We need to eliminate one of the variables, so let's use elimination method. First multiply (1) by 2

2*(1)\equiv\hspace{5}4x+2y=50

Now subtract (2) from 2*(1) in order to eliminate x:

2*(1)-(2)\\4x-4x+2y-3y=50-9\\-y=41

Solving for y:

Multiplying both sides by -1  

y=-41

Finally, replacing the value of y in (1)

2x-41=25

Solving for x:

add 41 to both sides:

2x=66

Multiply both sides by 1/2:

x=\frac{66}{2} =33

3 0
3 years ago
There is a special relationship between the lengths of the legs of a right triangle and the length of its hypotenuse. This relat
sattari [20]

Answer:

Hello, There!

<h2>Question</h2>

There is a special relationship between the lengths of the legs of a right triangle and the length of its hypotenuse. This relationship is known as the

<h2>Answer</h2>

Pythagorean Theorem.

Step-by-step explanation:

The Pythagorean Theorem states that the square of one leg (a) plus the square of the other leg (b) is equal to the square of the hypotenuse (c). This can be written as A^{2} + B^{2} = C^{2}.

3 0
2 years ago
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