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3 years ago

Input variable:Output variable:

Mathematics

1 answer:

vovangra [49]3 years ago

4 0

Answer:

A variable is an input variable if its Input property is Yes. Its value can be input from an external source, such as an Architect call flow. A variable whose Output property is Yes is an output variable.Since both properties can be set to yes, a variable can be both an input variable and an output variable.

Step-by-step explanation:

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Anyone help me pzzzzzzzzz

Marina86 [1]

The x values are the domain and they y values are the range. So the domain is {-2, 0, 2}. And the range is {-1, 0, 1}. So B is the answer.

4 0

3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago

I GIVEEE BRAILILSTTTTTTTT

Tema [17]

Answer:

umumumuykik.iu.fg

Step-by-step explanation:

lui;iou;uyfluylfuy;lui;uy;

8 0

3 years ago

PLEASE HELP!!

PSYCHO15rus [73]

Answer:

The bird is approximately 9 ft high up in the tree

Explanation:

The required diagram is shown in the attached image

Note that the tree, the cat and the ground form a right-angled triangle

Therefore, we can apply special trigonometric functions

These functions are as follows:

$sin(\alpha)=\frac{opposite}{hypotenuse} \\ \\ cos(\alpha)=\frac{adjacent}{hypotenuse} \\ \\tan(\alpha)=\frac{opposite}{adjacent}$

Now, taking a look at our diagram, we can note the following:

α = 25°

The opposite side is the required height (x)

The adjacent side is the distance between the cat and the tree = 20 ft

Therefore, we can use the tan function

This is done as follows:

$tan(\alpha)=\frac{opposite}{adjacent}\\ \\ tan(25)=\frac{x}{20}\\ \\x=20tan(25) = 9. 32 ft$ which is 9 ft approximated to the nearest ft

Hope this helps :)

5 0

3 years ago

Find the distance between M(-2,3) and N(8,2)

AnnZ [28]

Answer:

$d=\sqrt{101}$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the distance formula to find distance d:

$d=\sqrt{(8-(-2))^2+(2-3)^2}$

$d=\sqrt{(8+2)^2+(-1)^2}$

$d=\sqrt{(10)^2+1}$

$d=\sqrt{100+1}$

$d=\sqrt{101}$

6 0

3 years ago

Input variable:Output variable:​

Input variable:Output variable: