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3 years ago

If Rachel now owes a quarter of the money that she once owed, what could you do to find how much money she owes now?

Mathematics

2 answers:

MakcuM [25]3 years ago

8 0

Divide what she owed is the right answer

Alex73 [517]3 years ago

7 0

Answer:

Step-by-step explanation:

Given that Rachel now owes a quarter of the money that she once owed,

This implies that originally if he owns some amount say P dollars, now his loan is reduced to 1/4 of original hence now outstanding is P/4

So out of the four options given, first option is wrong because division to be done.

III is wrong because subtraction is not right.

IV is wrong since when reduced addition is not right

Only 2nd option is right.

Divide what she owed by 4.

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What is the slope of line ?

zzz [600]

Answer:The slope is m= 1/2

(0,-2) & (2,-1)

Step-by-step explanation:

(0,-2) & (2,-1)

m=y²-y¹/x²-x¹

m=(-1)-(-2)/2-0

m=1/2

7 0

3 years ago

What is the equation of the line that passes through the points (-2, -3) and (4, -5)

Jobisdone [24]

Answer:

x + 3y + 11 = 0 is the required equation.

Step-by-step explanation:

Here the given points are A( -2,-3) and B(4,-5)

Now, slope of the equation = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{-5 -(-3))}{4-(-2)} = \frac{-2}{6} =-\frac{1}{3}$

Hence, the slope of the equation is m = (-1/3)

Now, by POINT SLOPE FORMULA:

The equation of a line with slope m and point (x0, y0) is given as

(y - y0) = m (x -x0)

So, here the equation of line with (4, -5) is

$y - (-5) = -\frac{1}{3} (x - 4) \implies 3( y +5) = -x + 4$

or, 3y + 15 + x-4 = 0

or, x + 3y + 11 = 0

⇒ x + 3y + 11 = 0 is the required equation.

6 0

3 years ago

(6 8/25 ÷(−1)−(−0.8)·(−0.1))÷(−0.25÷1.25−1 3/5 ÷(−5 1/3 ))

const2013 [10]

Answer:

-64

Step-by-step explanation:

Given expression

$\left(6 \dfrac{8}{25}\div (-1)-(-0.8)\cdot (-0.1)\right)\div\left (-0.25\div 1.25-1 \dfrac{3}{5} \div\left(-5 \dfrac{1}{3} \right)\right)$

Perform all multiplications and divisions:

$6\dfrac{8}{25}\div (-1)=-6\dfrac{8}{25}\\ \\(-0.8)\cdot (-0.1)=0.08\\ \\-0.25\div 1.25=-\dfrac{0.25}{1.25}=-\dfrac{25}{125}=-\dfrac{1}{5}\\ \\1\dfrac{3}{5}\div \left(-5\dfrac{1}{3}\right)=-\dfrac{8}{5}\cdot \dfrac{3}{16}=-\dfrac{3}{10}$

Now subtract results in brackets:

$-6 \dfrac{8}{25}-0.08=-6.32-0.08=-6.4\\ \\-\dfrac{1}{5}-\left(-\dfrac{3}{10}\right)=-0.2+0.3=0.1$

Now, divide:

$-6.4\div 0.1=-\dfrac{6.4}{0.1}=-\dfrac{64}{1}=-64$

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3 years ago

In which quadrant is the point (-5,-3) located

schepotkina [342]

Answer:

In the 3rd quadrant

Step-by-step explanation:

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