What is the product of StartFraction 7 Over 9 EndFraction and One-fourth?

David charges $4 to wash all the windows of a car, inside and out. The amount of money he earns washing the windows must end in

nordsb [41]

Answer:

The possible digits are : 0, 2, 6, 4, 8

Step-by-step explanation:

Money charged by David to wash the windows of a car = $4

Let total number of cars he washed be x

Now, Total money earned by washing windows of a car = Money charged for washing all windows of one car × Total number of cars washed

⇒ Total money earned = 4 × x

So, the amount will always end in the digits which comes at the end of multiples of 4 because the amount will be always in the multiples of 4

⇒ 4 × 1 = 4 , 4 × 2 = 8 , 4 × 3 = 12 , 4 × 4 = 16 , 4 × 5 = 20 ......

So, the possible digits are : 0, 2, 6, 4, 8

4 0

3 years ago

What two rational expressions sum to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%2B2%7D%7Bx%5E%7B2%7D-9%2B8%20%7D" id="TexFor

bulgar [2K]

Answer:

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

Step-by-step explanation:

Given

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

Required

Fill in the gaps

Going by the given parameters, we have that

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

$x^2 - 9x + 8$ , when factorized is $(x-1)(x-8)$

Hence; the expression becomes

$\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}$

Combine Fractions

$\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}$

Simplify the denominators

$4x + 2 = A + B$

By direct comparison

$A = 4x$

$B = 2$

Hence, the complete expression is

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

3 0

3 years ago

Read 2 more answers

20 Point!

ludmilkaskok [199]

determinant: $\sqrt{b^2-4ac}$

(a) $x^2+4x+5=0\\D=4^2-4\cdot1\cdot5={-4}\\D$

D<0 means there are no real roots. there are two complex roots with imaginary components.

(b) D=16+20=36>0

D>0 means there are two real roots

(c) D = 20^2-4*4*25 = 0

D=0 means there is one real root with multiplicity 2

7 0

3 years ago

Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0

Artyom0805 [142]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

$x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}$

Next, solve the exponent and multiplications:

$x=\frac{4\pm \sqrt{16-52}}{2}$

Next, solve the subtraction:

$x=\frac{4\pm \sqrt{-36}}{2}$

Next, factor out i (i = √-1):

$x=\frac{4\pm \sqrt{36}i}{2}$

Next, solve the square root:

$x=\frac{4\pm 6i}{2}$

Lastly, divide and <u>your answer is:</u>

$x=2\pm 3i$

5 0

3 years ago

Read 2 more answers

What is the simplified product of (2x)(x^2)+(2x)(x)+(2x)(-2)+(3)(x^2)+(3)(x)+(3)(-2)

NikAS [45]

(2x)(x^2)+(2x)(x)+(2x)(-2)+(3)(x^2)+(3)(x)+(3)(-2)

Simplifying

(2x)(x2) + (2x)(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Remove parenthesis around (2x)

2x(x2) + (2x)(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Multiply x * x2

2x3 + (2x)(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Remove parenthesis around (2x)

2x3 + 2x(x) + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Multiply x * x

2x3 + 2x2 + (2x)(-2) + (3)(x2) + (3)(x) + (3)(-2)

Remove parenthesis around (2x)

2x3 + 2x2 + 2x(-2) + (3)(x2) + (3)(x) + (3)(-2)

Reorder the terms for easier multiplication:

2x3 + 2x2 + 2 * -2x + (3)(x2) + (3)(x) + (3)(-2)

Multiply 2 * -2

2x3 + 2x2 + -4x + (3)(x2) + (3)(x) + (3)(-2)

Multiply 3 * -2

2x3 + 2x2 + -4x + 3x2 + 3x + -6

Reorder the terms:

-6 + -4x + 3x + 2x2 + 3x2 + 2x3

Combine like terms: -4x + 3x = -1x

-6 + -1x + 2x2 + 3x2 + 2x3

Combine like terms: 2x2 + 3x2 = 5x2

-6 + -1x + 5x2 + 2x3

4 0

3 years ago