The first one and the third one are correct. because for the when you plug 1 on the first piece wise function you get 3.
f(3) =1. and f(1)=3 so f(1)>f(3)
Answer:
12.3
Step-by-step explanation:
Men: 132
Women: 90
Children: 36
Total: 258
Answer:
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Step-by-step explanation:
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).