Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
Answer:
The expression provided will have 2 terms (B.)
Step-by-step explanation:
3x(x + 1) + x
+ 3x + x
+ 4x
Can you be more specific on the problem
Answer:
Answers are in bold in explanation
Step-by-step explanation:
We are given the equation:
y = -7x + 8
The first x value is 0
y = -7(0) + 8
y = 8
(0, 8)
The next x value is 7
y = -7(7) + 8
y = -41
(7, -41)
Now we are given the Y value instead of X, so we do this:
36 = -7x + 8
Subtract 8 on both sides to leave -7x alone
28 = -7x
Divide by -7 on both sides to isolate x
-4 = x
(-4, 36)
