Answer:
t = 0
Before it starts rushing that's when it will be fastest
Step-by-step explanation:
For the water ib the tank to flow very fast it means that there is a big volume of water present.
And for volume of water to be present that much it means that the water must
have not leaked much or at all.
And for that it signifies large volume of water.
If we do the calculation we'd see that time will be actually equal to zero for the pressure and the volume of the water to be biggest.
V = 4500 (1 − 1 /50 t )^2
V = 4500
4500 = 4500(1- 1/50t)²
1 = 1- 1/50t
0 = -1/50t
t = 0
Answer:
X<2
Step-by-step explanation:
2x+4<8
subtract 4 from both sides
2x+4-4<8-4
simplify
2x<4
divide both by 2
2x/2<4/2
x<2
Answer:
i. 
ii. 
iii. 
iv. 
Step-by-step explanation:
Given
Time: 07 2(A) 5(B)
Calculating (a)
First, we need to list out the possible sample space, S of A


Probability of A being a 4 is the number of occurrence of 4 divided by the number of sample space


Hence;


Calculating (b)
First, we need to list out the possible sample space, S of B


Probability of B being a 8 is the number of occurrence of 8 divided by the number of sample space


Hence;


Calculating (c)
Using the sample space in (a)

Probability of A being less than 6 is the number of occurrence of less than 6 divided by the number of sample space


Hence;



Calculating (d)
Using the sample space in (b)

Probability of B being greater than 5 is the number of occurrence of greater than 5 divided by the number of sample space


Hence;



Answer:
Step-by-step explanation:
1 4/5*5/6
3/2 or 1 1/2
Answer:
time = 28 years
Step-by-step explanation:
Given,
principal amount = $10,000
rate = 4%
total amount = $30,000
According to compound interest formula

where, A = total amount
P = principal amount
r = rate
t = time in years
so, from the question we can write,



by taking log on both sides, we will get
=> log3 = t.log(1.04)

=> t = 28.01
So, the time taken to get the amount from 10000 to 30000 is 28 years.