Answer:
The answer is 3.785, but rounding it to the nearest hundredth is 3.68 or 3.79, depending on rather they wanted you to take the t and round up or just leave it off.
Answer:
B: The mean study time of students in Class B is less than students in Class A.
Step-by-step explanation:
To find out why answer B is the right answer, I will give you facts from each option.
Option A is false. <em>The mean study time in Class A is 4.8. Meanwhile in Class B it is 4. For Class A, sum up the 20 study times which is 96 and divide them by 20, you will get 4.8 hours of mean study time. For Class B, the sum of the 20 study times is 80, which divided by 20 will be 4.
</em>
Option B is True. <em>See previous explanation.
</em>
Option C is False. <em>The median study time in Class B is 4. The median study time in Class A is 4.8,
</em>
Option D is False. <em>The range in Class A is from 2 to 8. The range in Class B is from 2 to 7.
</em>
Option E is False: <em>The mean and median study time of these classes is different.</em>
Answer:
5.2 × 
Step-by-step explanation:
a number in scientific notation is expressed as
a × 
where 1 ≤ a < 10 and n is an integer
write 0.0052 as a number between 1 and 10, that is 5.2
we have to the move the decimal point 3 places to the left to retain it's value
3 places left means n is - 3
0.0052 = 5.2 ×
Answer: I'm not entirely sure, but maybe 1/x^2?
Answer:
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Step-by-step explanation:
![\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-15%5C%5C3%2615%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-40%5C%5C0%2624%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2B32%26-15%2B%28-40%29%5C%5C3%2B0%2615%2B24%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-55%5C%5C3%2639%5Cend%7Barray%7D%5Cright%5D)
