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2 years ago

For a scavenger hunt, Jim's mom distributed a bag of 875 jelly beans evenly into 25 plastic containers and hid them around the

Mathematics

1 answer:

kupik [55]2 years ago

6 0

Answer:

Jim only found 15 of the containers.

Step-by-step explanation:

If his mom hid 875 jelly beans evenly into 25 containers we can easily multiply 25 x 35 = 875, which means there were 35 jelly beans in each container.

Jim only found an amount of 385 jelly beans. To find out how many containers he found, all you have to do is divide 385 by 25 which gives us 15.4.

15.4 rounded to the nearest whole number is 15. So your answer would be that Jim found only 15 out of 25 containers.

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Determine the dependent variable in the statement:

Novay_Z [31]

Answer:

2 Amount of stretching

Step-by-step explanation:

answer is amount of stretching because

when she's flexible then only the amount of

stretching can be determined

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2 years ago

Factor 15y2 + 10y − 40.

Vaselesa [24]

see how it do it in the picture and hope it helps you..

3 0

2 years ago

Find the area of the triangle.

Vsevolod [243]

Answer:

20 m²

Step-by-step explanation:

Formula (Area of triangle):

$\text{A (Triangle)} = \dfrac{1}{2} \times \text{Base} \times \text{Height}$

From the triangle, we can see that the base of the triangle is "7 + 3" m and the height of the triangle is "4" m.

$\implies \text{A (Triangle)} = \dfrac{1}{2} \times (7 + 3) \times (4)$

Simplify the right-hand-side as needed to evaluate the area.

$\implies \text{A (Triangle)} = \dfrac{1}{2} \times (10) \times (4)$

$\implies \text{A (Triangle)} = \dfrac{40}{2} = 20 \ \text{m}^{2}$

Therefore, the area of the provided triangle is 20 m².

Learn more about this topic: brainly.com/question/15442893

8 0

2 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

2 years ago

(-5.975)(16.59) muiltilpy

olga nikolaevna [1]

Answer:

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Step-by-step explanation:

4 0

3 years ago

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