What is the square root of -6.25

Which graph shows the solution to this system of inequalities? y>-1/3x+1 y>2x-3

Mademuasel [1]

Given:

The system of inequalities is:

$y>-\dfrac{1}{3}x+1$

$y>2x-3$

To find:

The graph of the given system of inequalities.

Solution:

We have,

$y>-\dfrac{1}{3}x+1$

$y>2x-3$

The related equations are:

$y=-\dfrac{1}{3}x+1$

$y=2x-3$

Table of values for the given equations is:

$x$ $y=-\dfrac{1}{3}x+1$ $y=2x-3$

0 1 -3

3 0 3

Plot (0,1) and (3,0) and connect them by a straight line to get the graph of $y=-\dfrac{1}{3}x+1$ .

Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of $y=2x-3$ .

The signs of both inequalities are ">". So, the boundary line is a dotted line and the shaded region or each inequality lie above the boundary line.

Therefore, the graph of the given system of inequalities is shown below.

6 0

2 years ago

You prepare 10 scoops of dog food for 5 dogs, and prepare 16 scoops of dog food for 8 dogs. What

Svetllana [295]

Answer:

12 scoops of dog food are needed for 6 dogs,

Step-by-step explanation:

Proportions

The number of scoops of dog foods and the number of dogs are proportional variables.

We are given that 10 scoops of dog foods are used for 5 dogs. This gives a proportion of 10/5=2 scoops per dog.

We also know that 16 scoops are used for 8 dogs. The proportion is also 16/8=2 scoops per dog.

Thus, the constant of proportionality is 2.

For 6 dogs, you need to prepare 2*6 = 12 scoops of dog food.

12 scoops of dog food are needed for 6 dogs,

3 0

3 years ago

Find the midpoint of (-8,-10) and (8,0)

Allisa [31]

Answer:

(0,-5)

Step-by-step explanation:

You just have to find the middle of each one

From -8 to 8 there are 16 numbers so you divide 16 by 2 which would be 8 and add that to -8 giving you 0

From -10 to 0 there are 10 numbers divided by 2 is 5 so you add 5 to -10 giving you -5

This makes your midpoint (0,-5)

6 0

2 years ago

The city of Omaha decided to build a new parking garage in hopes of luring more people to the Old Market district.The city will

dimulka [17.4K]

Answer:

Given:

Mean, u = 135

Sample size, n = 42

Sample mean, x' = 126

Standard deviation = 16

Significance level = 0.05

1) The null and alternative hypotheses:

H0 : u = 135 (the revenue per day is $135)

H1 : u < 135 (the revenue per day is less than $135)

2) In this case, we have a left tailed test.

Let's use the formula:

$= \frac{x' - u}{s/ \sqrt{n}} = \frac{126 - 135}{16 / \sqrt{42}} = -3.645$

t = - 3.645

Critical value: at a significance level of 0.05, left tailed test,

tcritical = -1.683

We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.

3) Given, a = 0.05, df = 41, left tailed test,

t-value = 2.02

For the corresponding confidence interval, we have:

$CI = (x' - \frac{t * \sigma}{\sqrt{n}}, x' + \frac{t * \sigma}{\sqrt{n}})$

$CI = (126 - \frac{2.02 * 16}{\sqrt{42}}, 126 + \frac{2.02 * 16}{\sqrt{42}})$

CI = (121.014, 130.986)

4) Conclusion:

We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.

5 0

2 years ago

Write an inequality for the situation. The value, v, of the necklace is greater than $83

Sloan [31]

Hi There!

Inequality:

v>83

This inequality says that

v is greater than $83.

Hope it helps!

Have an awesome day!

$\huge\text{TheStarryNights :D}$

4 0

2 years ago