Answer:
115m
Step-by-step explanation:
Note that one of the face of a pyramid is a right angled triangle.
Since the pyramid was about 147m tall, the height of triangle will be 147m. If one of the faces is built with one of its faces at 52° to the incline, we can find the original length of one of its sides using SOH CAH TOA
tan(theta) = opposite/adjacent
Given theta = 52°, opposite = 147m (the side directly opposite the angle)
Substituting we have;
Tan52° = 147/adjacent
Adjacent = 147/tan52°
Adjacent = 114.8m
= 115m
Therefore 115m is the original length of one of its side
Answer:
445.2 square cm
Step-by-step explanation:
The surface area consists of area of two bases and area of three leteral faces. Each lateral face is a rectangle with length of 23 cm and width of 6 cm.
The area of rectangle is

So,

The area of base is given as 
Thus, the surface area is

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:
XY = X'Y' = 4 units
Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.
Find out more on equation at:
brainly.com/question/2972832
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The answer would be 49 + 42b if you multiply 7*7 and 7*6b
10(.5 + 6)=8
If you need me to explain, let me know.