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raketka [301]
3 years ago
9

Select all the equations that have no solution and state your reasoning as of "why" they do not have a solution. +6=5+ x+6=5+x −

2(−3)=-2+6 −2(x−3)=-2x+6 4−4=3+2 4−4x=3x+2 4(+1)=3(+2) 4(x+1)=3(x+2) 5−3=-3+4 5−3x=-3x+4
Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0

Equations:

x+6=5+x

-2(x-3)=-2x+6

4-4x=3x+2

4(x+1)=3(x+2)

5-3x=-3x+4

Answer:

x+6=5+x

5-3x=-3x+4

Step-by-step explanation:

Given

x+6=5+x

-2(x-3)=-2x+6

4-4x=3x+2

4(x+1)=3(x+2)

5-3x=-3x+4

Required:

Which have no solution

x+6=5+x

Subtract x from both sides

x -x+6 = 5 + x - x

6 = 5

x+6=5+x has no solution because 6 \ne 5

-2(x-3)=-2x+6

Open bracket

-2x + 6 = -2x + 6

Both sides are equal.

Hence, there is an Infinite\ Number of Solutions

4-4x=3x+2

Collect like terms

-3x - 4x = 2 - 4

-7x = -2

Solve for x

x = \frac{-2}{-7}

x = \frac{2}{7} --- This has a solution

4(x+1)=3(x+2)

Open brackets

4x + 4 = 3x + 6

Collect like terms

4x-3x = 6 - 4

x = 2 --- This has a solution

5-3x=-3x+4

Add 3x to both sides

5 - 3x + 3x = -3x + 3x + 4

5 = 4

5-3x=-3x+4 has no solution because 5 \ne 4

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According to historical records, the Great Pyramid of Giza was originally about 147 meters tall. Assuming it was built with its
vivado [14]

Answer:

115m

Step-by-step explanation:

Note that one of the face of a pyramid is a right angled triangle.

Since the pyramid was about 147m tall, the height of triangle will be 147m. If one of the faces is built with one of its faces at 52° to the incline, we can find the original length of one of its sides using SOH CAH TOA

tan(theta) = opposite/adjacent

Given theta = 52°, opposite = 147m (the side directly opposite the angle)

Substituting we have;

Tan52° = 147/adjacent

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Adjacent = 114.8m

= 115m

Therefore 115m is the original length of one of its side

6 0
4 years ago
23 cm
Alenkasestr [34]

Answer:

445.2 square cm

Step-by-step explanation:

The surface area consists of  area of two bases and area of three leteral faces. Each lateral face is a rectangle with length of 23 cm and width of 6 cm.

The area of rectangle is

A_{rectangle}=\text{length}\times\text{width}

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A_{rectangle}=23\times 6=138\ cm^2

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SA=2A_{base}+3A_{lateral\ face}\\ \\SA=2\cdot 15.6+3\cdot 138=445.2\ cm^2

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4 years ago
Line segment XY begins at (-6,4) and ends at (-2,4). The segment is reflected over the x-axis and translated left 3 units to for
Marat540 [252]

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

XY = \sqrt{(4-4)^2 + (-2 +6)^2} \\\\XY = \sqrt{0+16} \\\\XY = \sqrt{16} \\\\XY = 4

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:

XY = X'Y' = 4 units

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

Find out more on equation at:

brainly.com/question/2972832

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