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lutik1710 [3]
3 years ago
15

If 1,000 students take a test that has a mean of 40 minutes, a standard deviation of 8 minutes, and is normally distributed, how

many would you expect would finish in less than 40 minutes?
Mathematics
2 answers:
Nina [5.8K]3 years ago
7 0
500 because in a normal distribution 50% of the total falls below the mean 
Phoenix [80]3 years ago
7 0

Answer:

500

Step-by-step explanation:

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What number is equivalent to 23/8
Bumek [7]
23/8 = 46/16 = 92/32

Answer: 46/16, 92/32
5 0
3 years ago
Daniel dives into a swimming pool. The height of his head is represented by the function h(t) = -8t2 - 28t + 60, where t is the
8_murik_8 [283]
So, h(t) is how far is Daniel's head from the surface of the water, namely the surface itself is when the height is nill, so his head is at the surface and the height of it is just 0, thus h(t)  = 0.  Namely, what is "t" when h(t) is 0?

\bf h(t)=-8t^2-28t+60\implies \stackrel{h(t)}{0}=-8t^2-28t+60
\\\\\\
0=-2t^2-7t+15\implies 2t^2+7t-15=0\implies (2t+3)(t-5)=0
\\\\\\
\begin{cases}
2t+3=0\implies 2t=-3\implies &t=-\frac{3}{2}\\\\
t-5=0\implies &\boxed{t=5}
\end{cases}

clearly the seconds cannot be a negative unit, so is not -3/2.
6 0
2 years ago
JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw
luda_lava [24]

i. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the 
3 0
3 years ago
Which inequality matches the graph?
Alik [6]

b is the answer because it hits positive two on the x axis and -3 on the y axis

5 0
3 years ago
Evaluate and simplify <br><br> F(x)=3-6x^2 for f(x+3)
Olegator [25]

Insert x + 3 instead of x into the equation of the function f(x):

f(x) = 3 - 6x²

f(x + 3) = 3 - 6(x + 3)²

use (a + b)² = a² + 2ab + b²

= 3 - 6(x² + 2(x)(3) + 3²) = 3 - 6(x² + 6x + 9)

use distributive property

= 3 + (-6)(x²) + (-6)(6x) + (-6)(9) = 3 - 6x² - 36x - 54

combine like terms

= -6x² - 36x - 51

<h3>Answer: f(x + 3) = -6x² - 36x - 51</h3>
4 0
3 years ago
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