Answer:
Work done = 2307.17 j
Explanation:
Given data:
Work done = ?
Initial volume =18.38 L
Final volume = 7.11 L
Pressure = 2.02 atm
Solution:
work done = W = -PΔV
ΔV = V₂- V₁
work done = w = -P(V₂- V₁)
Now we will put the values in formula.
W = - 2.02 atm (7.11 L - 18.38 L)
W = - 2.02 atm (-11.27 L)
W = 22.77 atm.L
atm.L to joule:
22.77 atm.L × 101.325 J / 1L.atm
2307.17 j
x(0.5)(320)=(1.2)(48)(325)
160x=18720
x=18720/160
x=117
3 significant figures
