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Korolek [52]
3 years ago
6

A chemist needs 1.25 moles of sugar to dissolve in 1 liter of water how many grams of sugar needed

Chemistry
1 answer:
sdas [7]3 years ago
4 0

Answer:

The mass of sugar used is 427.5 grams.

Explanation:

The formula of common sugar is \mathrm{C_{12}H_{22}O_{11}}.

Its molar mass of molecule is 342 grams per mole.

The number of moles of sugar used is equal to '1.25'

\mathbf{Mole=\frac{Mass \ given \ in \ grams}{Molar \ mass \ of \ molecule \ in \ grams}}

\textrm{Mass in grams}=\textrm{Mole} \times \textrm{Molar mass of molecule in grams}

\textrm{Mass in grams}= 1.25\times342

\mathbf{Mass \ in \ grams=427.5 g}

(NOTE : <em>You can calculate molar mass by adding the mass of all the atoms present in the atom. </em>

<em>Mass of Oxygen (O) = 16  ;  Total number of Oxygen atoms present = 11</em>

<em>Mass of Hydrogen (H) =1  ;  Total number of Hydrogen Atoms present = 22</em>

<em>Mass of Carbon (C) = 12   ;  Total number of Carbon atoms present = 12</em>

<em>Total mass of molecule = 12 × 12 + 1 × 22 + 16 × 11 = 342</em>)

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Explanation:

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Suppose of nickel(II) chloride is dissolved in of a aqueous solution of potassium carbonate. Calculate the final molarity of chl
stich3 [128]

Answer: Molarity of chloride anion = 0.32 M

<em>Note: the question is missing some values. The full question is given below;</em>

<em>Suppose 7.26 g of nickel(II) chloride is dissolved in 350 mL of a 0.50 M aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the nickel(II) chloride is dissolved in it. Be sure your answer has the correct number of significant digits.</em>

Explanation:

Molarity or molar concentration is the number of moles (mol) of component per volume (liters) concentration of solution in mol/L or M

The mass of nickel (II) chloride is 7.26 g.

The volume of potassium carbonate is 350 mL = 0.35 L

The molarity of potassium carbonate solution is 0.50 M

The reaction of nickel (II) chloride and potassium carbonate is given below.

NiCl₂(aq) + KCO₃(aq) --------> KCl(aq) +NiCO₃(s)

The dissociation of nickel (II) chloride is given below.

NiCl₂   -----> Ni²⁺ + 2Cl⁻

The molar mass of nickel (II) chloride is  129.6 g/mol

The moles of nickel (II) chloride can be calculated by the formula given below;

No of moles  = mass(g) / molar mass (g/mol)

No of moles = 7.26 / 129.6 = 0.056 moles

Therefore, molarity of NiCl₂ = 0.056 moles/ 0.35 L = 0.16 M

The molarity of 1 mole nickel (ii) chloride is 0.16 m and according to dissociation of nickel (II) chloride, 1 mole of nickel (II) chloride gives 2 moles of chloride anion.

Therefore, the molarity of chloride anion = 0.16 * 2 = 0.32 M

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3 years ago
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