Glaciers can form in all these areas except

Which option is a mixture?<br> A. potassium<br> B. sugar<br> C. water<br> D. salad

PSYCHO15rus [73]

Answer:

D.Salad

Explanation:

A mixture is a substance that combines two or more substance that are physically combined. A mixture can be easily seperated by a physical means . A mixture is the combination of various substances that are not chemically combined .Examples of mixtures are cake and salad . The cake contains various substances like egg, flour and sugar. This mixture can be easily separated into it individual entities by a physical means .

Base on the option the only mixture among the option is salad . Salad is a a mixtures that combines substances like tomatoes , fruits and vegetable. The individual substances that makes up the salad can be easily separated.

Sugar is a compound . Water is a compound as it contains two elements and potassium is an element.

6 0

3 years ago

Read 2 more answers

Tungsten (W) and chlorine (Cl) form a series of compounds with the following compositions:_______.

deff fn [24]

Answer:

WCl₂, WCl₄, WCl₅, WCl₆

Explanation:

Molar Mass of Tungsten = 184 g/mol

Mass of Chlorine = 35.5 g/mol

In the first compound;

Percentage of tungsten = 72.17 %

Upon solving;

72.17 % = 184

100 % = Total mass

Total mass of compound = 254.95g

Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.

The Formular is WCl₂

In the second compound;

Percentage of tungsten = 56.45 %

Upon solving;

56.45 % = 184

100 % = Total mass

Total mass of compound = 325.95 g

Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.

The Formular is WCl₄

In the third compound;

Percentage of tungsten = 50.91 %

Upon solving;

50.91 % = 184

100 % = Total mass

Total mass of compound = 361.42 g

Mass of chlorine = 361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.

The Formular is WCl₅

In the fourth compound;

Percentage of tungsten = 46.39 %

Upon solving;

46.39 % = 184

100 % = Total mass

Total mass of compound = 396.64 g

Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.

The Formular is WCl₆

4 0

3 years ago

Place the following transitions of the hydrogen atom in order from longest to shortest wavelength of the photon emitted. Rank fr

gizmo_the_mogwai [7]

Answer:

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Explanation:

We can use the Rydberg formula which relates the wavelength of the photon emissions to the principle quantum numbers involved in the transition:

$\frac{1}{\lambda}=R((\frac{1}{n_1^2})-(\frac{1}{n_2^2}))$

with $n_1$ final n, and $n_2$ initial n

evaluating for each transition:

7 to 4 $\frac{1}{\lambda} = R((\frac{1}{4^2})-(\frac{1}{7^2}))= R(1/16-1/49)=R(0.042)$

5 to 3 $\frac{1}{\lambda}= R(1/9-1/25)=R(0.071)$

4 to 2 $\frac{1}{\lambda}= R(1/4-1/16)=R(0.1875)$

3 to 2 $\frac{1}{\lambda}= R(1/4-1/9)=R(0.139)$

Note that the above formula is written for $\frac{1}{\lambda}$ , so lower $\frac{1}{\lambda}$ value obtained involves higher $\lambda$ .

So we should order from lower to higher $\frac{1}{\lambda}$

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Note: Take into account that longer wavelength involves lower energy ( $E=\frac{hc}{\lambda}$ ).

3 0

3 years ago

Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode

miskamm [114]

Answer:

544.522 Hours

Explanation:

a) Mass = 12.5 kg = 12500 g

Now, Number of moles is given as

No of moles = Mass of Cr / Molar mass of Cr

$=\frac{12500}{52}$

= 240.38 moles

$Cr^{3+}\Rightarrow$ 3 mols of electrons are required

$\Rightarrow 240.38\times3 =721.14\text{mol of e-}$

Converting moles of e- to coulombs of charge, (1 mol of electrons = 96500 C )

Q =721.14 mol×96500 C/mol

=69590010 of charge

We know that, Q = I×t

where Q is charge, I is current and t is time required.

$\Rightarrow t =\frac{Q}{I}$

$=\frac{69590010}{35.5}$

=196281.97 seconds

$=\frac{1.96281\times10^5}{3600}$

=544.522 Hours

3 0

3 years ago

In an acid-base titration, a base or acid is gradually added to the other until they have completely neutralized each other. Sin

Xelga [282]

Answer:

1/10 or 0.1

Explanation:

Quantities at which equivalence can be obtained are:

95, 96, 97, 98, 99, 100, 101, 102, 103, 104

Number of quantities = N = 10

Probability that the equivalency is obtained exactly at 100 mL can be calculated as follows:

P(X = 100) = (Number of favourable outcomes) / (Total Number of Outcomes)

P(X = 100) = 1/10

P(X = 100) = 0.1

5 0

4 years ago