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Sedbober [7]
4 years ago
9

Given: x + 2 <-5.

Mathematics
1 answer:
timurjin [86]4 years ago
4 0

We have

x+2.

We can simplify this expression to

x.

Which can be written as

x\in(-\infty, -7)

or

x\in\{a\in\mathbb{R}\wedge a.

Hope this helps.

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What is the answer to this​
zubka84 [21]

Answer: C. 124

Step-by-step explanation:

In parallelograms, any two consecutive interior angles add to 180 degrees. CDA and BCD are consecutive interior angles. Since the measure of angle CDA is 56 and the sum of CDA and BCD equal 180, then to find the value of BCD, evaluate 180-56.

180 - 56 = 124

4 0
3 years ago
Let X have the uniform distribution U(0, 2) and let the conditional distribution of Y , given that X = x, be U(0, x). Find the j
Elina [12.6K]

Answer:

f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x

E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \

Step-by-step explanation:

We have two random variables X and Y. X \sim Unif(0,2) and given that X=x, Y has uniform distribution (0,x)

From the definition of the uniform distribution we have the densities for each random variable given by:

f_X (x) =\frac{1}{2} , 0\leq x\leq 2

f_{Y|X} (y|x) = \frac{1}{x}, 0\leq y \leq x

And on this case we can find the joint density with the following formula:

f(x,y) = f_{Y|X}(y|x) f_X (x)

And multiplying the densities we got this:

f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x

Now with the joint density we can find the expected value E(Y|x) with the following formula:

E(Y|x) = \int y f_{Y|X}(y|x)dx

And replacing we got:

E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \

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4 years ago
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