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PolarNik [594]
3 years ago
5

The frog is climbing out of a well that is 50 Feet deep. The frog can climb 7 feet per hour but then a rest for an hour and it s

lips back 3 feet while resting. How long will it take for the frog to get out of the well?
Mathematics
2 answers:
Darya [45]3 years ago
7 0

Answer: 12 Hours after 48 Leaps

Step-by-step explanation: A simple way of looking at this problem is like this:

7 (-3) = 4 | 4 x 1

7 (-3) = 8 | 4 x 2

7 (-3) = 12 | 4 x 3

7 (-3) = 16 | 4 x 4

7 (-3) = 20 | 4 x 5

7 (-3) = 24 | 4 x 6

7 (-3) = 28 | 4 x 7

7 (-3) = 32 | 4 x 8

7 (-3) = 36 | 4 x 9

7 (-3) = 40 | 4 x 10

7 (-3) = 44 | 4 x 11

7 (-3) = 48 | 4 x 12

Each leap back will become a multiple of four. Most of the time it will always be a number that’s close to the total number but not quite the total number itself. That will be your answer.

Mumz [18]3 years ago
5 0

7-3=4 feet per hour

50 : 4 = 12,5  hour

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(3x^2-2x+4)+(5x^2+6x-8) - Combine like terms
8x^2+4x-4
(f+g)(x)=8x^2+4x-4
5 0
3 years ago
Construction paper cost $0.10 per square inch. How much will Susan spend to make this figure out of construction paper? ​
AfilCa [17]

The will spend $33.60 (option C) to make the figure out of construction paper, if the construction paper cost $0.10 per square inch.

Step-by-step explanation:

The given is,

                 Construction paper cost $0.10 per square inch

                 Pyramid diagram with dimensions

Step:1

               Formula to calculate the area of pyramid,

                            Area, A = lw+l\sqrt{(\frac{w}{2}) ^{2} + h^{2} } +w \sqrt {(\frac {l} {2}) ^{2} + h^{2} }..............(1)

             Where,

                        l - Base length

                      w - Base width

                      h - Height of pyramid

             From given,

                       l = 12 inches

                     w = 12 inches

            For height of pyramid,

             By using Pythagorean theorem,

                                       Hypotenuse^{2} = Base^{2} + Height ^{2}.................(2)

              For right angle triangle,

                                             Base = \frac{12}{2} = 6 inches

              Equation (2) becomes,

                                                  8^{2} = 6^{2} + Height^{2}

                                        Height^{2} = 8^{2} - 6^{2}

                                        Height^{2} = 64 -36 = 28

                                          Height = \sqrt{28}

                                          Height = 5.2915 inches

                    h - 5.2915 inches

                Equation (1) becomes,

                       A = (12)(12)+(12)\sqrt{(\frac{12}{2}) ^{2} + 5.2915^{2} } +(12 )\sqrt {(\frac {12} {2}) ^{2} + 5.2915^{2} }

                          = 144+(12)\sqrt{(36+27.999)} +(12)\sqrt{(36 + 27.999)}    

                          = 144+(12)\sqrt{63.999}+(12)\sqrt{63.999}

                          = 144+(12)(7.9999)+(12)(7.9999)

                          =144+95.999+95.999

                          =335.998      

                          ≅ 336 square inches

                Where,

                         $0.10 per square inch ( from given)

                 Paper cost of total figure = 336 square inches

                                                             = 336 × 0.10

                                                             = $ 33.60

Result:

           The will spend $33.60 to make the figure out of construction paper, if the construction paper cost $0.10 per square inch.

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So, you just need to draw the points

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As for the trigonometric function, we have to start from the parent function y=\sin(x) and derive the graph of its child function via transformations:

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You can see the two functions in the image below. You can also see that the two graphs cross 4 times, meaning that the equation

y_1=y_2 has four solutions.

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Answer:

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