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PolarNik [594]
3 years ago
5

The frog is climbing out of a well that is 50 Feet deep. The frog can climb 7 feet per hour but then a rest for an hour and it s

lips back 3 feet while resting. How long will it take for the frog to get out of the well?
Mathematics
2 answers:
Darya [45]3 years ago
7 0

Answer: 12 Hours after 48 Leaps

Step-by-step explanation: A simple way of looking at this problem is like this:

7 (-3) = 4 | 4 x 1

7 (-3) = 8 | 4 x 2

7 (-3) = 12 | 4 x 3

7 (-3) = 16 | 4 x 4

7 (-3) = 20 | 4 x 5

7 (-3) = 24 | 4 x 6

7 (-3) = 28 | 4 x 7

7 (-3) = 32 | 4 x 8

7 (-3) = 36 | 4 x 9

7 (-3) = 40 | 4 x 10

7 (-3) = 44 | 4 x 11

7 (-3) = 48 | 4 x 12

Each leap back will become a multiple of four. Most of the time it will always be a number that’s close to the total number but not quite the total number itself. That will be your answer.

Mumz [18]3 years ago
5 0

7-3=4 feet per hour

50 : 4 = 12,5  hour

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nadezda [96]

Answer:

The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

Step-by-step explanation:

Represent the provided data as follows:

Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:

P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}

The number of Protestants surveyed is, <em>n</em> (Protestants) = 99.

The number of Protestants who were calm for 2 days,

<em>n</em> (Protestants who were calm for 2 days) = 6

The required probability is:

P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}\\=\frac{6}{99}\\ =0.060606\\\approx0.061

Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

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2 years ago
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Veseljchak [2.6K]

Answer:

Step-by-step explanation:

R(0,0)

A=((0+2a)/2,(0+2b)/2)=(a,b)

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B=((2a+2c)/2,(2b+2d)/2)=(a+c,b+d)

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3 years ago
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Answer:

a. Ameribank-$15,157.50

b. Capital Two-$4,646.25

Step-by-step explanation:

a. Tad's savings is $15,000, we calculate his total amount at the end of the year for each bank:

#Ameribank

A=P+I=P+PRT\\\\=15000+15000\times 0.0105\times 1\\\\=\$15,157.50

#Huffington( we use the effective rate to calculate the compound amount):

i_m=(1+i/m)^m-1\\\\=(1+0.0095/12)^[12}-1=0.009541\\\\A=P(1+i_m)^n\\\\=15000(1.009541)^1\\\\=\$15,143.12

#Sixth-Third, Take 1 yrs=52 weeks:

i_m=(1+i/m)^m-1\\\\=(1+0.01/52)^{52}-1=0.01005\\\\A=15000(1.01005)^1\\\\=\$15,150.74

#Hence, Ameribank is the best option as his money grows to $15,157.50 which is greater than all the remaining two options.

b. We use the compound interest formula A=P(1+r/n)^{nt} to determine which bank gives the best option:

#Capital Two. r=3.75%, n=12,t=4

A=P(1+r/n)^{nt}\\\\=4000(1+0.0375/12)^{12\times4}\\\\=\$4,646.25

#J.C Morgan, t=2, r=3.55% n=12

A=P(1+r/n)^{nt}\\\\=4000(1+0.0355/12)^{12\times 2}\\\\=\$4,293.87

#Silverman Slacks, n=12,t=3, r=3.65%

A=P(1+r/n)^{nt}\\\\=4000(1+0.0365/12)^{12\times3}\\\\=\$4,462.14

We compare the investment amounts after t years:

Capital>Silver>Morgan=4646.25>4462.14>4293.87

Hence, Capital two is the best option with an investment amount of $4,646.25

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x = 2.75

Now that we have the length of the shorter board, we can add 7.5 to it to get the larger one.

2.75 + 7.5 = 10.25

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