Answer:
9
Step-by-step explanation:
You gave the answer right in your question
Answer:
associative property
Step-by-step explanation:
Answer:
C) 0 ≤ x ≤ 25
Step-by-step explanation:
We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300
A)x ≥ 0
Refer the graph
At x = 0
f(x)=300
On increasing the value of x , f(x) increases but at x = 12 it starts decreasing
So, x ≥ 0 can also have f(x)<300
So, Option A is wrong
B)−5 ≤ x ≤ 30
At x = -5
f(x) = 100
So, Option B is wrong since we require f(x) is greater or equal to 300
c)0 ≤ x ≤ 25
At x = 0
f(x)=300
At x = 12 , it starts decreasing
At x = 25
f(x)=300
So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25
D)All real numbers
At x = 30
f(x)=0
But we require f(x) greater or equal to 300
Hence Option C is true
A=3,500×(1+0.03÷2)^(2×20)
A=6,349.06
Answer: -10m + 30
Step-by-step explanation:
<u>Given expression</u>
(m - 3) (-10)
<u>Expand parentheses and apply the distributive property</u>
=m · (-10) - 3 · (-10)
<u>Simplify by multiplication</u>
=
Hope this helps!! :)
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