Answer:
y=4/3x-1/3
Step-by-step explanation:
Answer:
r= -10
Step-by-step explanation:
Multiply both sides by -3/4
remove parenthesis
move constant to the right
change the signs
A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
Flipping over the trigonometric functions of sine, cosine and tangent we have the following respectively
1/cscФ (sinФ), 1/secФ (cosФ) and 1/cotФ (tanФ). These are the identities for which they numerically equal when the numerator and denominator of these fractions are swapped.
1 cup = 1/2 pint, so where it says 4 cups we'll just read 2 pints.
1. In one show we serve 30 × 2 pints of small and 42 × 6 pints of regular.
Total = 30 × 2 + 42 × 6 = 60 + 252 = 312 pints
Answer: 312 pints
2. 8 pints per gallon, 2 gallons per container makes 16 pints per container.
312 pints / 16 pints per container = 19.5 containers
We round up since we need a whole number of containers.
Answer: 20 containers
We can't really see question 3.
