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harkovskaia [24]
3 years ago
12

Which of the following expressions is the inverse of the function y=3x+4

Mathematics
2 answers:
zubka84 [21]3 years ago
7 0
To find the inverse of a function, we swap x and y then solve for y
So with this, we take y = 3x + 4 and make it x = 3y + 4. Now we solve for y
x = 3y + 4
Subtract 4 from both sides
x - 4 = 3y
Divide both sides by 3
\frac{x-4}{3} =y
wel3 years ago
7 0

Options:

A. y = 3x - 4

B. y = -3x - 4

C. y = x - 4 / 3

D. y = x + 4 / 3

The answer is option C when your doing inverse functions you need to switch the variables but substituting x with y. So, the equation would look like this:

  • y = 3x + 4 ---> x = 3y + 4
  • x = 3y + 4
  • Subtract 4 on both sides:
  • Then divide 3 on both sides: " \frac{x - 4}{3} =y or option C "

Hope this helps!

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The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
pav-90 [236]

Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

Year (x)       First Year f(x)      Second Year s(x)

2009                  785                        756

2010                   740                        785

2011                    690                        710

2012                   732                         732

2013                   781                          755

Which of the following statements is true based on the data in the table?

  • The solution to f(x) = s(x) is x = 2012.
  • The solution to f(x) = s(x) is x = 732.
  • The solution to f(x) = s(x) is x = 2011.
  • The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
8 0
3 years ago
A triangle has sides of lengths 8, 15, and 17. Is it a right triangle? Explain.
natta225 [31]

Answer:

Step-by-step explanation:

8^2 + 15^2 = ?

64 + 225 = 17^2

289 = 289

\sqrt{289} = \sqrt{289\\} \\ 17 = 17

4 0
3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
I don't get it please help.
pshichka [43]

Answer:

Answer

Step-by-step explanation:

y=-2/7x+5=

slope: -2/7

y-intercept: (0,5)

I think it's what the question is if not then sorry.

8 0
3 years ago
-14(3a+6)=12(6-4a)+12 and steps please
Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

14(3a+6)+12(6-4a)+12=0 (using distributive property)

42a+84+72-48a+12=0 ( adding the like terms )

-6a+168=0

-6a=-168

6a=168

a=\frac{168}{6}

Therefore a=28

Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

8 0
3 years ago
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