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harkovskaia [24]
2 years ago
12

Which of the following expressions is the inverse of the function y=3x+4

Mathematics
2 answers:
zubka84 [21]2 years ago
7 0
To find the inverse of a function, we swap x and y then solve for y
So with this, we take y = 3x + 4 and make it x = 3y + 4. Now we solve for y
x = 3y + 4
Subtract 4 from both sides
x - 4 = 3y
Divide both sides by 3
\frac{x-4}{3} =y
wel2 years ago
7 0

Options:

A. y = 3x - 4

B. y = -3x - 4

C. y = x - 4 / 3

D. y = x + 4 / 3

The answer is option C when your doing inverse functions you need to switch the variables but substituting x with y. So, the equation would look like this:

  • y = 3x + 4 ---> x = 3y + 4
  • x = 3y + 4
  • Subtract 4 on both sides:
  • Then divide 3 on both sides: " \frac{x - 4}{3} =y or option C "

Hope this helps!

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Andrew uses 630 one-inch unit cubes to completely fill the inside of a rectangular box. Which could be the dimensions of the box
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7 0
3 years ago
Simplify (Are all division)<br><br>2+4i<br>3i<br><br>3+2i<br>4+i<br><br>2i^11
Alla [95]

We\ know:\ i=\sqrt{-1}\to i^2=-1

\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i

\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i

2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i


Used:\ (a+b)(a-b)=a^2-b^2

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3 years ago
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Lesechka [4]
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7 0
3 years ago
What is halfway between 400,000 and 500,000?
goldenfox [79]

Answer:

450,000

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__________________________________________________________

Questions related to this topic? Please ask me in the <em>comments</em> box.

4 0
1 year ago
Read 2 more answers
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