All categories

4 years ago

Question 19 please help

Mathematics

1 answer:

vfiekz [6]4 years ago

4 0

√105
if u see its factor are only 3,5,7 so it cant be simplify
answer should be √105
B

You might be interested in

A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a white chip then another white chip witho

saul85 [17]

The answer is 8/81...

5 0

3 years ago

two urns contain white balls and yellow balls the first urn contains 7 white balls and 7 yellow balls and the second urn contain

faltersainse [42]

Answer:

The correct answer option is b) $\frac{1}{6}$ .

Step-by-step explanation:

We are given that the first urn contains 7 white balls and 7 yellow balls and the second urn contains 3 white balls and 6 yellow balls. We are to find the probability that both balls drawn are white.

This means that the first must be white and the second ball must also be white.

P (w, w) = $\frac{7}{14}$ × $\frac{3}{9}$ = $\frac{1}{6}$

Therefore, the probability that both the balls drawn are white is 1/6.

5 0

3 years ago

A woman earns $2900 per month and budgets $290 per month for food. What percent of her monthly income is spent on food?

Vladimir [108]

Earnings: $2900

Expenditure on food: $290

Percentage expenditure on food = Expenditure on food / Earnings times 100

= $290/$2900 * 100 = 10%

6 0

3 years ago

Where did the negative go? 8th grade math

Ierofanga [76]

Answer:

Since the equation is to the power of 4, the negative sign to the power of 4 will give a positive sign.

5 0

3 years ago

In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from

Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

a. 

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals $\frac{180}{600}=0.3$ ie 30%

b.

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

c.

z-score of the sample proportion assuming null hypothesis is:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of working people aged 65–69 (0.3)
p is the proportion assumed under null hypothesis. (0.27)
N is the sample size (600)

then z= $\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } }$ = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

3 0

3 years ago

Read 2 more answers