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Tomtit [17]
4 years ago
6

Question 19 please help

Mathematics
1 answer:
vfiekz [6]4 years ago
4 0
√105
if u see its factor are only 3,5,7 so it cant be simplify
answer should be √105
B
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A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a white chip then another white chip witho
saul85 [17]
The answer is 8/81...
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3 years ago
two urns contain white balls and yellow balls the first urn contains 7 white balls and 7 yellow balls and the second urn contain
faltersainse [42]

<u>Answer:</u>

The correct answer option is b) \frac{1}{6}.

<u>Step-by-step explanation:</u>

We are given that the first urn contains 7 white balls and 7 yellow balls and the second urn contains 3 white balls and 6 yellow balls. We are to find the probability that both balls drawn are white.

This means that the first must be white and the second ball must also be white.

P (w, w) = \frac{7}{14} × \frac{3}{9} = \frac{1}{6}

Therefore, the probability that both the balls drawn are white is 1/6.

5 0
3 years ago
A woman earns $2900 per month and budgets $290 per month for food. What percent of her monthly income is spent on food?
Vladimir [108]

Earnings: $2900

Expenditure on food: $290

Percentage expenditure on food = Expenditure on food / Earnings times 100

= $290/$2900 * 100 = 10%

6 0
3 years ago
Where did the negative go? 8th grade math
Ierofanga [76]

Answer:

Since the equation is to the power of 4, the negative sign to the power of 4 will give a positive sign.

5 0
3 years ago
In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from
Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

H_{0}: p=27%

H_{a}: p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

<em>a. </em>

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals \frac{180}{600}=0.3 ie 30%

<em>b.</em>

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

H_{0}: p=27%

H_{a}: p>27%

<em>c.</em>

z-score of the sample proportion assuming null hypothesis is:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of working people aged 65–69 (0.3)
  • p is the proportion assumed under null hypothesis. (0.27)
  • N is the sample size (600)

then z=\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } } = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

3 0
3 years ago
Read 2 more answers
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