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2 years ago

If one diagonal of a rhombus is 15 meters long and it’s area is 157.5 square meters, find the measures of the other diagonal

Mathematics

1 answer:

ycow [4]2 years ago

7 0

Answer:

The other diagonal measures 21m

Step-by-step explanation:

In this question, we are tasked with calculating the length of the second diagonal of as Rhombus given the measure of the surface area of the rhombus and the length of the other diagonal

Mathematically, for a rhombus having two diagonals $d_{1}$ and $d_{2}$ , the area of the rhombus can be calculated mathematically using the formula below;

A = 1/2 × $d_{1}$ × $d_{2}$

From the question, we can identify that A = 157.5 $m^{2}$ and $d_{1}$ = 15m

we input these in the formula;

157.5 = 1/2 × 15 × $d_{2}$

315 = 15 $d_{2}$

$d_{2}$ = 315/15

$d_{2}$ = 21m

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Lapatulllka [165]

Answer:

The Answer is: y = -1/4x + 6

Step-by-step explanation:

Given point: (4, 5)

Given equation: y = -1/4x - 11

Slope: m = -1/4, a parallel line will have the same slope.

Start with the point slope form and solve for y:

y - y1 = m(x - x1)

y - 5 = -1/4(x - 4)

y - 5 = -1/4x + 1

y = -1/4x + 1 + 5

y = -1/4x + 6

Proof:

f(x) = -1/4x + 6

f(4) = -1/4(4) + 6

= -1 + 6 = 5, giving (4, 5)

Hope this helps!! Have an Awesome day!!! :-)

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Shkiper50 [21]

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2 years ago

Josh drew ∆ ABC with mm∠A = 40°, m∠B = 60° and m∠ C = 80°. Howard drew ∆ XYZ with m∠Y = 60° and m∠ Z = 80°. What can you say abo

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Step-by-step explanation:

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3 years ago

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

tiny-mole [99]

let me edit your question as:

Which two equations are true?

Eq1:

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

Eq2:

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

Eq3:

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

Eq1:

$(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\$

Eq2:

$6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1$

Eq3:

$2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\$

we observed that none of the equation has two same values on both sides thus none of the three equations is true.

Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true

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choli [55]

Answer:

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Step-by-step explanation:

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