The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.
The graph is attached below.
- We are given a quadratic function.
- A polynomial equation of degree two in one variable is a quadratic equation.
- The function given to us is :
- y = x² - 5x - 36
- We need to find the solution of the quadratic function.
- To find the roots, let y = 0.
- x² - 5x - 36 = 0
- Use the quadratic formula.
- In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
- x = [-b±√b²-4ac]/2a
- x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
- x = (5 ± √25 + 144)/2
- x = (5 ± √169)/2
- x = (5 ± 13)/2
- x = 9 or x = -4
To learn more about functions, visit :
brainly.com/question/12431044
#SPJ1
The answer is F(x) = 900x + 600
Let x stands for the number of months
The apartment is rented for $900 a month, so every month it will be paid 900x (for example, for one month (x = 1), you will pay 900 · 1 = $900, for three months (x = 5), you will pay 900 · 5 = $4500, etc.)
A security deposit is paid only once and is not dependent on the number of months. So, its value is only 600.
These two values must be summed up because both must be paid, nothing is to subtract. Therefore, the function f(x) for apartments that rent for $900 a month and a security deposit of $600 is:
f(x) = 900x + 600
Answer:
9 x 100 + 8 x 10 + 7 x 1000 = 7,980
Answer:
C: 2x^5
Step-by-step explanation:
Leading coefficients are the numbers written in front of the variable with the largest exponent. Just like regular coefficients, they can be positive, negative, real, or imaginary as well as whole numbers, fractions or decimals. For example, in the equation -7x^4 + 2x^3 - 11, the highest exponent is 4.