Answer:
The answer is
Step-by-step explanation:
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A model is made of a car. the car is 10 feet long and the model is 7 inches long. what is the ratio of the length of the car to
1 answer:
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Answer:
B.
Step-by-step explanation:
The given quadratic trinomial is;
Comparing this to , we have a=5,b=17,c=6.
Two factors of 30 that add up to 17 is 15 and 2.
We split the middle term to obtain;
We factor by grouping;
Factor further
The correct answer is B.
So hmm let's take a peek at the cost first
so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x
so, more than likely an insurance agency is charging them 300x for coverage
anyway, thus the cost C(x) = 250,000 + 300x
now, the Revenue R(x), is simple is jut price * quantity
well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits
so... let's see what the price say y(x) is
so.. now we know y(x) = -30x+7400
now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"
that simply means R(x) = -30x²+7400x
now, for the profit P(x)
the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)
P(x) = (7400x - 30x²) - (250,000+300x)
P(x) = -30x² + 7100x - 250,000
now, where does it get maximized? namely, where's the maximum for P(x)?
well
and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum
so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x
so, more than likely an insurance agency is charging them 300x for coverage
anyway, thus the cost C(x) = 250,000 + 300x
now, the Revenue R(x), is simple is jut price * quantity
well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits
so... let's see what the price say y(x) is
so.. now we know y(x) = -30x+7400
now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"
that simply means R(x) = -30x²+7400x
now, for the profit P(x)
the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)
P(x) = (7400x - 30x²) - (250,000+300x)
P(x) = -30x² + 7100x - 250,000
now, where does it get maximized? namely, where's the maximum for P(x)?
well
and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum
Answer:
C.
.
Step-by-step explanation:
Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.
Roman spent $62.75
This implies that,
Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.
This implies that,
Using guess and check means we substitute into the given equation.
A) We substitute
into both equations.
Both equations are not satisfied.
B)
We substitute
into both equations.
Both equations are not satisfied.
C)
We substitute into both equations.
Both equations are satisfied.
Hence the solution is,
D) We substitute
into both equations.
Both equations are not satisfied.
C.
Step-by-step explanation:
Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.
Roman spent $62.75
This implies that,
Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.
This implies that,
Using guess and check means we substitute into the given equation.
A) We substitute
Both equations are not satisfied.
B)
We substitute
Both equations are not satisfied.
C)
We substitute
Both equations are satisfied.
Hence the solution is,
D) We substitute
Both equations are not satisfied.