You can do this by going in a competition or by collecting fund or by selling some of your old items to some one who you know
Answer:
4 minutes.
Explanation:
The rate of flow from the tap is 2 gallons every six second
which comes out to be 1 gallons per 3 seconds.
so for 80 gallons we can simply
3 * 80 = 240 which is 240 seconds.
Thus it would take 4 minutes to fill up the 80 gallon tub.
Answer:
Required return is 8.75%
Explanation:
Given,
FV (Face Value) is $1,000
PV (present Value) is computed as:
PV = FV × Price
= $1,000 × 101.4%
= $1,014
Nper (Number of years) is 8 years
PMT (Monthly payment) is computed as:
PMT = FV × Coupon rate
= $1,000 × 9%
= $90
r (Required return) is computed by using the excel formula:
=Rate(nper, pmt, pv, fv, type)
= Rate (8,90,-1014,1000,0)
= 8.75%
Answer:
A
Explanation:
Net present value is the present value of after-tax cash flows from an investment less the amount invested.
Only projects with a positive NPV should be accepted. A project with a negative NPV should not be chosen because it isn't profitable.
When choosing between positive NPV projects, choose the project with the highest NPV first because it is the most profitable.
NPV can be calculated using a financial calculator
Cash flow in year 0 = $-165,000
Cash flow in year 1 - 6 = $45,000
I = 12%
NPV = $20,013.33
the project should be approved because NPV is positive
To find the NPV using a financial calculator:
1. Input the cash flow values by pressing the CF button. After inputting the value, press enter and the arrow facing a downward direction.
2. after inputting all the cash flows, press the NPV button, input the value for I, press enter and the arrow facing a downward direction.
3. Press compute
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>
