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Olegator [25]
3 years ago
9

Problem 1:

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

A = 2

D = 1

B = 4

C = 3

Step-by-step explanation:

Height of water in bathtub is a function of water in bathtub.

P(t) = w ; t = time ; w = height of water.

A: P (0)=0 ; At time, t = 0 ; height of water = 0, there is no water on bathtub

2: The bathtub starts out with no water.

D: P (20) = 0 ; At time, t = 20 ; w = 0 ;the tub is empty.

1: After 20 minutes, the bathtub is empty.

B:P (4)= 10 `; At t = 4, w = 10 ; height of water in bath tub is 10

4: The height of the water is 10 inches after 4 minutes

C:P (10) = 4 ; At t = 10, w =4, height of water in bathtub = 4 inches

3: After 10 minutes, the height of the water is 4 inches.

.

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HOTS Question:<br>Solve: 2xy /x+y = 3/2, x+y≠0 and xy / 2x-y = -3 / 10, 2x-y≠0
andreyandreev [35.5K]

x = \frac{1}{2} and y =  -  \frac{3}{2}

Step-by-step explanation:

\frac{2x}{x + y} =  \frac{3}{2}

=  > \frac{x + y}{xy} =  \frac{4}{3}

=  >  \frac{1}{x} +  \frac{1}{y} =  \frac{4}{3}---- Eq. 1

Then,

\frac{xy}{2x - y} =  -  \frac{3}{10}

=  >  \frac{2x - y}{xy} =  -  \frac{10}{3}

=  >  -  \frac{1}{x} +  \frac{2}{y} =  -  \frac{10}{3}-- Eq. 2

Let

\frac{1}{x} = uand

\frac{1}{y} = v.

Then, from Eq. 1 & 2, we get:

u + v =  \frac{4}{3} and

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=  > 3u + 3v = 4and

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By adding, we get,

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=  > v =  \frac{ - 6}{9}

=  > v =  -  \frac{2}{3}

Substituting "y" got above in Eq.1, we get,

\frac{1}{x} -  \frac{2}{3} =  \frac{4}{3}

=  >  \frac{1}{x} =  \frac{6}{3} = 2

=  > x = 2

Hence,

x =  \frac{1}{2}

=  > y =  -  \frac{3}{2}

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Answer:

Step-by-step explanation:

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