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Olegator [25]
3 years ago
9

Problem 1:

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

A = 2

D = 1

B = 4

C = 3

Step-by-step explanation:

Height of water in bathtub is a function of water in bathtub.

P(t) = w ; t = time ; w = height of water.

A: P (0)=0 ; At time, t = 0 ; height of water = 0, there is no water on bathtub

2: The bathtub starts out with no water.

D: P (20) = 0 ; At time, t = 20 ; w = 0 ;the tub is empty.

1: After 20 minutes, the bathtub is empty.

B:P (4)= 10 `; At t = 4, w = 10 ; height of water in bath tub is 10

4: The height of the water is 10 inches after 4 minutes

C:P (10) = 4 ; At t = 10, w =4, height of water in bathtub = 4 inches

3: After 10 minutes, the height of the water is 4 inches.

.

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The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What fraction of the games did they win?
Amanda [17]
They won 6/11 games.

When you add the games they won, lost, and tied you see that they played a total of 11 games. It tells you that they won 6 games so you would put 6 as the numerator and 11 as the denominator and get 6/11.
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3 years ago
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3 0
3 years ago
Find BC if BD = X + 29, AD = x = 39, AC = 20, and BC = x + 19
nalin [4]

Answer:

10 units

Step-by-step explanation:

We are given that

BD=x+29

AD=x+39

AC=20

BC=x+19

AC=AB+BC

20=AB+x+19

AB=20-x-19=1-x

AD=AB+BD

x+39=1-x+x+29

x=30-39=-9

Substitute the value of x=-9

Then , we get BC=-9+19=10 units

Answer: BC=10 units

5 0
3 years ago
What is the numerical expression 5/8 - 5/12 (3-1/4) + 2/3<br><br> A.9<br> B.2<br> C.1/2<br> D.1/9
Ronch [10]
The answer is B. 7/48
Hope this helps!
8 0
3 years ago
The height in feet, h, of a model rocket t seconds after launch is given by the equation h(t) = 3+70t - 16t^2. The average rate
andriy [413]

Answer:

The average rate of change

\frac{dh}{d t} = 70 (1) - 16(2t)

At   t = 1

\frac{dh}{d t} = 70 (1) - 16(2t) = 38

at t=3



Step-by-step explanation:

<u><em>Step(I)</em></u>:-

The given function  h(t) = 3+70t - 16t²

                          \frac{dh}{d t} = 70 (1) - 16(2t)

The       \frac{dh}{d t} = 70 (1) - 16(2t) =0

           70 - 32 t = 0

     ⇒   70 = 32 t

   ⇒     t = \frac{70}{32} = \frac{35}{16}

<em>Step(ii</em>):-

The average rate of change in h(t) between t = 1 second and t = 3 second

\frac{dh}{d t} = 70 (1) - 16(2t)

At   t = 1

\frac{dh}{d t} = 70 (1) - 16(2t) = 38

At t = 3



8 0
3 years ago
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