How many lines of reflectional symmetry does an equilateral triangle have?

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

7 0

There are 3 lines of reflectional symmetry in an equilateral triangle

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2sin^2 2x=2 In the domain [0,2pi) What can x equal ( in radians).

lions [1.4K]

Bear in mind that, when it comes to trigonometric functions, the location of the exponent can be a bit misleading, however recall that sin²(θ) is really [ sin( θ )]²,

$\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2}
\\\\\\
sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1}
\\\\\\
sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)$

$\bf \measuredangle 2x=sin^{-1}(\pm 1)\implies \measuredangle 2x=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\\\\
-------------------------------\\\\
\measuredangle 2x=\cfrac{\pi }{2}\implies \measuredangle x=\cfrac{\pi }{4}\qquad \qquad \qquad \qquad \measuredangle 2x=\cfrac{3\pi }{2}\implies \measuredangle x=\cfrac{3\pi }{4}$

3 0

2 years ago

The perpendicular bisector of the line segment connecting the points (-3,8) and (-5,4) has an equation of the form y = mx + b. F

omeli [17]

Answer:

Step-by-step explanation:

find the slope

$\frac{4-8}{-5-(-3)} =\frac{-4}{-2} \\\\slope=2\\y=mx+b\\y=2x+b\\$