How many lines of reflectional symmetry does an equilateral triangle have?
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First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.
Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.
Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.