Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
El transporte celular ayuda a las células a mantener la homeostasis manteniendo rangos normales dentro de todas las células de un organismo.
Limiting factors for snakes can include frogs, grasshoppers, farmers, pesticides, weather, climate, the environment, and various other abiotic and biotic factors.
Those specified however were also specified within the prompt. These are limiting factors because they can limit or help excel the snake population growth, yet in this prompt it is shown to greatly diminish the growth.
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