It is greater than 5/7. 5/7<1, and sqrt(5)>2
Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
3/5 is the lowest term. 3/5 = 15/25. Does this help?
The expression √(128x⁸y³z⁹) is equivalent to the expression 8x⁴yz⁴ √(2yz). Then the correct option is C.
The missing options are given below.
<h3>What is an equivalent expression?</h3>
The equivalent is the expressions that are in different forms but are equal to the same value.
The expression is given below.
⇒ √(128x⁸y³z⁹)
Then the expression is given below.
⇒ √[(64 × 2)(x⁴)²(y²y)(z⁸z)]
⇒ 8x⁴yz⁴ √(2yz)
Then the correct option is C.
More about the equivalent link is given below.
brainly.com/question/889935
#SPJ1
Answer:
D
Step-by-step explanation:
Geometric sequence has to do with a pattern of multiplication, and D has a pattern of times 4 if that makes any sense