Length of KL is 17 units
Given that;
L is mid point of KM
KL = 2x - 3
LM = x + 7
Find:
Length of KL
Computation:
We know that,
L is mid point of KM
So,
KL = LM
2x - 3 = x + 7
2x - x = 7 + 3
x = 10
So,
Length of KL = 2x - 3
Length of KL = 2(10) - 3
Length of KL = 20 - 3
Length of KL = 17 units
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Answer:
-49
Step-by-step explanation:
First you convert them in improper fraction then it comes
35/3 × -21/5
With the help of cross multiplication we get
7×-7
And then 7×-7 = -49
Answer:
Step-by-step explanation:
Let's FOIL out both sides and then see where we are after that:
Let's combine like terms now and get everything on one side of the equals sign and set the polynomial equal to 0 to solve for x:
0 = 8x - 4 and we can factor out a 4 to give us:
0 = 4(2x - 1)
Either 4 = 0 or 2x - 1 = 0. Well it's obvious that 4 does not equal 0, so 2x-1 must equal 0. Then
2x = 1 so
x = 1/2 or choice A on the left.
Answer: Don’t quite understand what you are asking but the Y-Intercept = 15, and the slope would be -7. Hope this helps you
Step-by-step explanation:
Actually the position function with respect to time under constant acceleration is:
a=g
v=⌠g dt
v=gt+vi
s=⌠v
s=gt^2/2+vit+si
So if vi and si are zero then you just have:
s=gt^2/2
Notice that it is not gt^2 but (g/2) t^2
So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...
Anyway....
sf=(a/2)t^2+vit+si
(sf-si)-vit=a(t^2)/2
2(sf-si)-2vit=at^2
a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero
a=(2s)/t^2
