All categories

3 years ago

Which of the following statement is not a reason for sampling?

Mathematics

1 answer:

VladimirAG [237]3 years ago

3 0

Answer:

Studying every single instance of a thing is impractical or too expensive

Step-by-step explanation:

With sampling we a have a lot of data without much effort.

You might be interested in

Please answer and explain why.

SashulF [63]

A. because you have to multiply the sides and add them together

5 0

3 years ago

What is The polynomial for the question above

frosja888 [35]

A polynomial of degree n with roots $r_1,r_2,...,r_n$ can be represented as: $f(x)=A(x-r_1)(x-r_2)\cdot...\cdot(x-r_n)$ , where A is a constant (The same "a" that appears outside the parentheses in the field where you will type the polynomial). In this question, the number of roots is 4, because the degree of f(x) is 4. If a polynomial has only real coefficients, the complex roots appear in pairs of conjugates. So, since $-3+4i$ is a zero, $-3-4i$ is a zero too. Then, we have the 4 zeros. Hence, $f(x)$ will be in the form:

$f(x)=A(x-5)^2(x-(-3+4i))(x-(-3-4i))\\\\f(x)=A(x-5)^2(x^2-(-3+4i)x-(-3-4i)x+(-3+4i)(-3-4i))\\\\f(x)=A(x^2-10x+25)(x^2+6x+25)\\\\f(x)=A(x^4-4x^3-10x^2-100x+625)$

4 0

3 years ago

Second grade Solve using algorithm. Draw chips and bundle when you can

Anastasy [175]

Idk what your answer will be i had it then i lost it sorry

4 0

3 years ago

Suppose there was a cancer diagnostic test was 95% accurate both on those that do and those do not have the disease. If 0.4% of

Musya8 [376]

Complete Question

Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.

Answer:

The probability is $P(C | A) = 0.0042$

Step-by-step explanation:

From the question we are told that

The probability that the test was accurate given that the person has cancer is

$P(A | C) = 0.95$

The probability that the test was accurate given that the person do not have cancer is

$P(A | C') = 0.90$

The probability that a person has cancer is

$P(C) = 0.004$

Generally the probability that a person do not have cancer is

$P(C') = 1- P(C)$

=> $P(C') = 1- 0.004$

=> $P(C') = 0.996$

Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as

$P(C | A) = \frac{P(A | C) * P(C)}{P(A|C) * P(C) + P(A| C') * P(C')}$

=> $P(C | A) = \frac{ 0.95 * 0.004 }{ 0.95 * 0.004 + 0.90 * 0.996}$

=> $P(C | A) = 0.0042$

7 0

3 years ago

After 3.5 hours, Patrick had traveled 217 miles. If he travels at a constant speed, how far will he have traveled after 4 hours

Ede4ka [16]

Answer: He would have traveled 248 miles

Explanation: This is a ratio

To find how many miles he would have traveled after 4 hours, we need to apply the information givin into a ration table

(We can put miles on the top and hours on the bottom)

217 ?
------- ------
3.5 4

Now, we can do two things:
1. cross multiply
we would take 217 times 4 (868) and divide that by 3.5 (248)

2. Divide the top and bottom by 3.5 (numerator= 62 denominator= 1)
multiply 62 by 4 to get 248

Hope this helps!

6 0

3 years ago