Find the slope of the curve y=-3x-x^2 at the point (-1,2)

Mathematics

1 answer:

Elodia [21]3 years ago

6 0

Answer:

slope = - 1

Step-by-step explanation:

The slope of the curve m is measured by

m = $\frac{dy}{dx}$ at x = a

Differentiate using the power rule

$\frac{d}{dx}$ (a $x^{n}$ ) = na $x^{n-1}$

Given

y = - 3x - x², then

$\frac{dy}{dx}$ = - 3 - 2x

x = - 1 → $\frac{dy}{dx}$ = - 3 - 2(- 1) = - 3 + 2 = - 1 ← slope at (- 1, 2 )

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