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3 years ago

A triangle has side lengths measuring 2x + 2 ft, x + 3 ft, and n ft.

Mathematics

1 answer:

Liula [17]3 years ago

5 0

Answer: x – 1 < n < 3x + 5

Step-by-step explanation:In a triangle sum of any two sides is always greater than the third side.

Now, the sides of the triangle are given to be :

2x + 2, x + 3 , n

Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.

By using the property that sum of two sides is always greater than the third side in a triangle.

⇒ 2x + 2 + x + 3 > n

⇒ 3x + 5 > n ......(1)

Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.

So, by the property, we have :

n + x + 3 > 2x + 2

⇒ n > x - 1 ...........(2)

From both the equations (1) and (2) , We get :

x – 1 < n < 3x + 5

Therefore, The answer is x – 1 < n < 3x + 5

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Let f(x) represent a function.

STatiana [176]

Answer:

For $f(x+\frac{5}{4})$ , $f(x)$ is translated $\frac{5}{4}$ units left.

For $f(x)-\frac{5}{4}$ , $f(x)$ is translated $\frac{5}{4}$ units down.

Step-by-step explanation:

The transformation of $f(x)\rightarrow f(x+C)$ means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of $f(x)\rightarrow f(x)+C$ means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of $f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0$ , so, the function translates left by $\frac{5}{4}$ units.

Similarly, in the transformation of $f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}$ , so, the function translates down by $\frac{5}{4}$ units.

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3 years ago

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jenyasd209 [6]

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The side lengths are 9cm, 6cm, 10cm, 5cm, 4cm, and 4cm.

So the perimeter is the following...

Perimeter = 9 + 6 + 10 + 5 + 4 + 4 = 38cm total

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